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Lana71 [14]
3 years ago
5

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What are transition elements?​
Chemistry
1 answer:
Lesechka [4]3 years ago
6 0

Answer:

Transition elements are elements which have partially filled d-orbitals and form at least one or more stable ions.

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A car with a mass of 1,200 kilograms is moving around a circular curve at a uniform velocity of 20 meters per second. The centri
Helga [31]
The answer is 80 m.

Centripetal force (F) is a force that makes body move around a circular curve. The unit of force is N (N = kg * m/s²).
It can be represented as:
F= \frac{m* v^{2} }{r}
where:
m - mass
v - velocity
r - radius of the curve

We have:
m = 1,200 kg
V = 20 m/s
F = 6,000 N = 6,000 kg * m/s²

We need radius of the curve:
r = ?

So, if <span>F= \frac{m* v^{2} }{r}, then:
</span>    r= \frac{3* v^{2} }{F}
⇒ r =  \frac{1200 kg * (20m/s)^{2} }{6000 kg*m/s^{2} }
⇒ r= \frac{1200*400*kg*m^{2}*s^{2}  }{6000kg*m/s^{2} }
⇒ r= \frac{480,000m}{6000}
⇒ r=80m


6 0
4 years ago
Consider a sample of 11.2 g of ice initially at 0.0 C. How much energy in kilojoules is required to melt the ice and warm it to
oksian1 [2.3K]

Answer:

1034.88J

Explanation:

Given that:

mass (m) = 11.2 g, initial temperature = 0°C, final temperature = 22°C, the specific heat capacity of water (C) = 4.2 J/g°C

Temperature difference (ΔT) = final temperature - initial temperature = 22 - 0 = 22°C

The quantity of heat (Q) required to melt the ice can be calculated from the equation:

Q = mCΔT

Q = 11.2 g × 4.2 J/g°C × 22°C

Q = 1034.88J

5 0
3 years ago
What describes how the bond between two oxygen atoms is formed
HACTEHA [7]

The bond that exist between two oxygen atoms is called a double covalent bond. This bond involves the sharing of four electrons to obtain a more stable structure. This type of bond is much stronger than the single covalent bond. They are much harder to break.

4 0
4 years ago
Joshua uses his thermometer (experimental value) and finds the boiling point of ethyl alcohol to be 75°C 75 ° C . The accepted v
QveST [7]

75-80 = 5 = .0625 X 100 = 6.25%

80 80

8 0
3 years ago
What temperature, in C, would be required for 1.70 grams of oxygen gas
olga_2 [115]

Answer:

2408.1 °C

Explanation:

Given data:

Mass of oxygen = 1.70 g

Volume occupy = 9.75 L

Pressure of gas = 799 torr (799/760 = 1.1 atm)

Temperature = ?

Solution:

Formula:

PV = nRT

First of all we will determine the number of moles of oxygen.

Number of moles = mass/ molar mass

Number of moles = 1.70 g/ 32 g/mol

Number of moles = 0.05 mol

Now we will put the values.

R = general gas constant = 0.0821 atm.L/ mol.K

T = PV/nR

T = 1.1 atm× 9.75 L /0.05 mol ×0.0821 atm.L/ mol.K

T = 10.725 /0.004

T = 2681.25 K

kelvin to °C

2681.25 K - 273.15 = 2408.1 °C

8 0
3 years ago
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