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HACTEHA [7]
3 years ago
8

Synthesis Decompisition O Combustion O Single Displacement O Double Displacement

Chemistry
1 answer:
BabaBlast [244]3 years ago
4 0

Answer:

Synthesis

Explanation:

Nothing else works

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An experiment produced 0.10 g CO2 with a volume of 0.056 L at STP. If the accepted density of CO2 at STP is 1.96 g/L, what is th
Mandarinka [93]
The experimental density of CO2 at STP is 0.10/0.056=1.78 g/L. The percent error equals to (1.96-1.78)/1.96*100%=9.18%. So the answer is 9.18%.
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3 years ago
A large pot (10 kg) of beef stew is left out on the kitchen counter to cool. The rate of cooling, in kJ/min, equals 1.955 (T-25)
olga_2 [115]

Answer:

16 minutes

Explanation:

First, we need to calculate the amount of heat needed to cool the beef stew:

Q = mcΔT

Where <em>m</em> is the mass, <em>c</em> is the heat capacity and <em>ΔT</em> is the variation of the temperature.

Q = 10x4x(40 - 90)

Q = -2000 kJ

So, the beef stew needs to lost 2000 kJ to cool.

With the initial temperature at 90ºC, the rate of cooling(r) will be:

r = 1.955x(90 - 25)

r = 127.075 kJ/min

So, to lose 2000 kJ, will be necessary:

t = Q/r

t = 2000/127.075

t = 16 minutes

5 0
3 years ago
What is the symbol for aluminum and sulphur ?​
borishaifa [10]
<h2><em>Al2 S3</em></h2>

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<h2><em>hope it helps</em><em>!</em></h2>
4 0
3 years ago
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