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blsea [12.9K]
3 years ago
10

The current in a long solenoid of radius 4 cm and 19 turns/cm is varied with time at a rate of 8 A/s. A circular loop of wire of

radius 6 cm and resistance 3 Ω surrounds the solenoid. Find the electrical current induced in the loop (in µA).
Physics
1 answer:
Dmitry [639]3 years ago
4 0

Answer:

Current induced in the loop = 0.032 mA

Explanation:

emf induced in the solenoid using Faraday law e = \frac{-d\phi}{dt}=-\pi R^{2} \frac{dB}{dt}

here, R is the radius of solenoid which is constant &  \frac{dB}{dt} is the change in magnetic field.

Magnetic field inside the solenoid from B=μ0 n i -----(i)

Where, i is the current in the coil.

n= numbers of turn in per meter length.

n=19 x 100 turns/m

Differentiating equation (i)

\frac{dB}{dt} = μ0 n \frac{dI}{dt}

= 4 π 10-7 x 1900 x 8 =0.019

E = 3.14 X 0.42^{2}  X 0.019 =0.095 m V

Hence electrical current induced in the loop =  \frac{E}{R} =\frac{0.095}{3} = 0.032 mA

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Two parallel-plate capacitors have the same plate area, but the plate gap in capacitor 1 is twice as big as capacitor 2. If capa
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Answer:

Capacitance of the second capacitor = 2C

Explanation:

\texttt{Capacitance, C}=\frac{\varepsilon_0A}{d}

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Let C₁ be the capacitance of first capacitor with area A₁ and gap between plates d₁.

We have    

              \texttt{Capacitance, C}_1=\frac{\varepsilon_0A_1}{d_1}=C

Similarly for capacitor 2

               \texttt{Capacitance, C}_2=\frac{\varepsilon_0A_2}{d_2}=\frac{\varepsilon_0A_1}{\frac{d_1}{2}}=2\times \frac{\varepsilon_0A_1}{d_1}=2C

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6 0
3 years ago
Suppose that you measure a galaxy's redshift, and from the redshift you determine that its recession velocity is 30,000 (3×10^4)
anyanavicka [17]

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1.4 billion light years away

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According to Hubble's law

v=H_0D\\\Rightarrow D=\frac{v}{H_0}\\\Rightarrow D=\frac{3\times 10^{4}}{65}\times 3.2\times 10^6\\\Rightarrow D=1476923076.92307\ ly\\\Rightarrow D=1.4\times 10^9\ ly

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5 0
3 years ago
An athlete jumping vertically on a trampoline leaves the surface with a velocity of 8.5 m/s upward. what maximum height does she
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<span>Her center of mass will rise 3.7 meters. First, let's calculate how long it takes to reach the peak. Just divide by the local gravitational acceleration, so 8.5 m / 9.8 m/s^2 = 0.867346939 s And the distance a object under constant acceleration travels is d = 0.5 A T^2 Substituting known values, gives d = 0.5 9.8 m/s^2 (0.867346939 s)^2 d = 4.9 m/s^2 * 0.752290712 s^2 d = 3.68622449 m Rounded to 2 significant figures gives 3.7 meters. Note, that 3.7 meters is how much higher her center of mass will rise after leaving the trampoline. It does not specify how far above the trampoline the lowest part of her body will reach. For instance, she could be in an upright position upon leaving the trampoline with her feet about 1 meter below her center of mass. And during the accent, she could tuck, roll, or otherwise change her orientation so she's horizontal at her peak altitude and the lowest part of her body being a decimeter or so below her center of mass. So it would look like she jumped almost a meter higher than 3.7 meters.</span>
8 0
3 years ago
What quantity is the rate of change of velocity? Displacement Acceleration Final velocity
MariettaO [177]

Answer:

Acceleration

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The quantity of the rate of change of velocity is termed the acceleration of the body.

Acceleration is the rate of change of velocity with time;

  A  = \frac{v - u}{t}  

A is the acceleration

v is the final velocity

u is the initial velocity

t is the time taken

 

7 0
3 years ago
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