The drag force acting on the rocket is 80N.
<h3>Give an explanation of drag force?</h3>
The divergence in velocity between the fluid and the item, also known as drag, exerts a force on it. Between the liquid and the solid object, there should be motion. Drag is absent in the absence of motion.
The air molecules are more compressed (pushed together) on the surfaces that are facing the front while being more dispersed (spread out) on the surfaces facing the back. Turbulent flow, which occurs when air layers split from the surface and start to swirl, is what causes this.
The drag force acting on the rocket F = ma
Given,
m = 4kg, a = 20ftm/s²
Substituting m and a values in the above formula,
The drag force acting on the rocket F = 4×20
The drag force acting on the rocket F = 80N.
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Answer:
Initial velocity =
b) Height it reaches = 44.145 m
Explanation:
Using the first equation of motion we have

here
v is the final velocity
u is the initial velocity
a is the acceleration of the object
t is time
When the ball reaches it's highest point it's velocity will become 0 as it will travel no further
Also the acceleration in our case is acceleration due to gravity (
) as the ball moves in it's influence alone with '-' indicating downward direction
Thus applying the values we get

b)
By 3rd equation of motion we have

here s is the distance covered
Applying the value of u that we calculated we get

Answer:
the distance of image from the vertex is 45 cm and the image formed is in the glass.
Explanation:
distance of object, u = - infinity
radius of curvature, R = - 15 cm
refractive index, n = 1.5
Let the distance of image is v.
Use the formula

The image is in the glass.
Not much changes, but there are some great pressure so some hills may form.