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2 years ago

What is the internal energy of 3.00mol of N2 gas at 25c?

Physics

1 answer:

Citrus2011 [14]2 years ago

3 0

Answer:

18600j

Explanation:

It is given that,

Number of moles = 3

Temperature, T = 25°C = 25+273 = 298 K

The internal energy of N₂ gas is given by :

U=f\times nRTU=f×nRT

f is degrees of freedom. For diatomic gas, degree of freedom is equal to 5/2. So,

\begin{gathered}U=\dfrac{5}{2}\times 3\times 8.31\times 298\\\\U=18572.85\ J\end{gathered}

5×3×8.31×298

U=18572.85 J

U = 18600 J

So, the internal energy of the gas is 18,600 J

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To solve this problem it is necessary to apply the kinematic equations of angular motion.

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Using the expression of angular acceleration we can find the to then find the torque, that is,

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2 years ago

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Answer:

Option (d) is correct.

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