From the given pH, we calculate the concentration of H+:
[H+] = 10^-pH = 10^-5.5
We then use the volume to solve for the number of moles of H+:
moles H+ = 10^-5.5M * 4.3x10^9 L = 13598 moles
From the balanced equation of the neutralization of hydrogen ion by limestone written as
CaCO3(s) + 2H+(aq) → Ca2+(aq) + H2CO3(aq)
we use the mole ratio of limestone CaCO3 and H+ from their coefficients, which is 1 mole of CaCO3 is to react with 2 moles of H+, to compute for the mass of the limestone:
mass CaCO3 = 13598mol H+(1mol CaCO3/2mol H+)
(100.0869g CaCO3/1mol CaCO3)(1kg/1000g)
= 680 kg
Answer:
Hope this helps!
Explanation:
I would help you, but I won't. Because you take others people points without helping them and but random words. So, since you are doing that I won't be helping you <3. Thanks for the points idiot.
Answer : The partial pressure of
and
are, 84 torr and 778 torr respectively.
Explanation : Given,
Mass of
= 15.0 g
Mass of
= 22.6 g
Molar mass of
= 197.4 g/mole
Molar mass of
= 32 g/mole
First we have to calculate the moles of
and
.

and,

Now we have to calculate the mole fraction of
and
.

and,

Now we have to partial pressure of
and
.
According to the Raoult's law,

where,
= partial pressure of gas
= total pressure of gas
= mole fraction of gas


and,


Therefore, the partial pressure of
and
are, 84 torr and 778 torr respectively.