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Mama L [17]
3 years ago
13

Brandi rolls a fair Six-sided Number cube flips a fair coin, and then rolls the number cube again. Which outcome is part of samp

le space?
Mathematics
1 answer:
Komok [63]3 years ago
7 0

Answer:

Options aren't given but explanation and answer is below:

Step-by-step explanation:

First action/trial  -  Rolling a fair dice (6-sided number cube)

Second action      -  Flipping a fair coin

Third action        -   Rolling a fair dice

In this experiment, all the equipment are fair. What this means is that there is no bias; <u>every face of each equipment has an equal chance of emerging tops.</u>

In your options, you should have three values per option.

The first would be the number resulting from the first throw of dice.

The second would be head or tail; which are the only two faces of a coin.

The third would be the number resulting from the second throw of dice.

So ONE of those options will be a part of the sample space, which is enlisted below:

Trial A:  {1, 2, 3, 4, 5, 6}

Trial B:   {Head, Tail}

Trial C:   {1, 2, 3, 4, 5, 6}

* If there's an option like {9, Tail, 2} it will be wrong, because it has an element "9" which does not fall within the prescribed sample space.

* Also, if we follow the order in which Brandi conducted this experiment, an option like {Head, 6, 5} will be wrong, since the elements are wrongly placed.

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For example:

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The Area of a rectangle is 3x2 + 9x square inches. The length of the rectangle is 3x inches.
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Width of the rectangle is x + 3 in

Step-by-step explanation:

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A train leaves boston at 2:00 pm. a second train leaves the same city in the same direction at 6:00 pm. the second train travels
AURORKA [14]
\boxed {\boxed { \text {Distance = Speed x Time}}}

<u>First Train:</u>
Time taken = 9 hours (2pm to 11pm)
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Distance = Time x Speed = 9x

<u>Second Train:</u>
Time taken = 5 hours (6pm to 11pm)
Speed = x + 48
Distance = Time x Speed = 5(x + 48)

Since both the distance they traveled are the same, we equate the distance to solve for x.

<u>Solve for x:</u>
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Answer: The spend of the two trains are 60 mph and 108 mph.
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