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3 years ago

13

Brandi rolls a fair Six-sided Number cube flips a fair coin, and then rolls the number cube again. Which outcome is part of samp

le space?

1 answer:

Komok [63]3 years ago

7 0

Answer:

Options aren't given but explanation and answer is below:

Step-by-step explanation:

First action/trial - Rolling a fair dice (6-sided number cube)

Second action - Flipping a fair coin

Third action - Rolling a fair dice

In this experiment, all the equipment are fair. What this means is that there is no bias; <u>every face of each equipment has an equal chance of emerging tops.</u>

In your options, you should have three values per option.

The first would be the number resulting from the first throw of dice.

The second would be head or tail; which are the only two faces of a coin.

The third would be the number resulting from the second throw of dice.

So ONE of those options will be a part of the sample space, which is enlisted below:

Trial A: {1, 2, 3, 4, 5, 6}

Trial B: {Head, Tail}

Trial C: {1, 2, 3, 4, 5, 6}

* If there's an option like {9, Tail, 2} it will be wrong, because it has an element "9" which does not fall within the prescribed sample space.

* Also, if we follow the order in which Brandi conducted this experiment, an option like {Head, 6, 5} will be wrong, since the elements are wrongly placed.

You might be interested in

What is the equation when y=5x+4 is reflected over the x-axis, y-axis & y=x?

tigry1 [53]

Answer:

A) $y=-5x-4$

B) $y=-5x+4$

C) $y=\frac{x-4}{5}$

Step-by-step explanation:

So we have the equation:

$y=5x+4$

Let's write this in function notation. Thus:

$y=f(x)=5x+4$

A)

To flip a function over the x-axis, multiply the function by -1. Thus:

$f(x)=5x+4\\-(f(x))=-(5x+4)$

Simplify:

$-f(x)=-5x-4$

B) To flip a function over the y-axis, change the variable x to -x. Thus:

$f(x)=5x+4\\f(-x)=5(-x)+4$

Simplify:

$f(-x)=-5x+4$

C) A reflection over the line y=x is synonymous with finding the inverse of the function.

To find the inverse, switch x and f(x) and solve for f(x):

$f(x)=5x+4$

Switch:

$x=5f^{-1}(x)+4$

Subtract 4 from both sides:

$x-4=5f^{-1}(x)$

Divide both sides by 5:

$f^{-1}(x)=\frac{x-4}{5}$

And we're done :)

7 0

3 years ago

1 foot is equal to 12 inches how many inches are in 3 feet 10 unches

USPshnik [31]

Answer:

46 in

Step-by-step explanation:

3x12=36+10=46

3 0

2 years ago

Read 2 more answers

A girl scout troop sold cookies. If the girls sold 5 more boxes the second week than they did the first, and if they double the

valina [46]

Answer:

Boxes sold first week = 104

Boxes sold second week =x+5= 104+5=109

Boxes sold third week = 109 times 2= 218

Step-by-step explanation:

Let x be the number of boxes sold in first week

the girls sold 5 more boxes the second week

So number of boxes sold in second week is x+5

they double the sales of the second week for the third week

So number of boxes sold in third week is 2 (x+5)

Total boxes sold is 431

$x+x+5+2(x+5)=431$

$x+x+5+2x+10=431$

$4x+15=431$

subtract 15 from both sides

$4x=416$

divide by 4 on both sides

$x=104$

Boxes sold first week = 104

Boxes sold second week =x+5= 104+5=109

Boxes sold third week = 104 times 2= 218

4 0

3 years ago

Rita received a $90 gift card for a coffee store. She used it in buying some coffee that cost $8.07 per pound. After buying the

laila [671]

Subtract 41.58 by 9 then devide that number by 8.07 to get the amount of pounds purchased your answer is 6

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4 years ago

A college infirmary conducted an experiment to determine the degree of relief provided by three cough remedies. Each cough remed

KiRa [710]

Answer:

$p_v = P(\chi^2_{4,0.05} >3.81)=0.43233$

Since the p values is higher than the significance level we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we don't have significant differences between the 3 remedies analyzed. So we can say that the 3 remedies ar approximately equally effective.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

NyQuil Robitussin Triaminic Total

No relief 11 13 9 33

Some relief 32 28 27 87

Total relief 7 9 14 30

Total 50 50 50 150

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is no difference in the three remedies

H1: There is a difference in the three remedies

The level os significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{total col * total row}{grand total}$

And the calculations are given by:

$E_{1} =\frac{50*33}{150}=11$

$E_{2} =\frac{50*33}{150}=11$

$E_{3} =\frac{50*33}{150}=11$

$E_{4} =\frac{50*87}{150}=29$

$E_{5} =\frac{50*87}{150}=29$

$E_{6} =\frac{50*87}{150}=29$

$E_{7} =\frac{50*30}{150}=10$

$E_{8} =\frac{50*30}{150}=10$

$E_{9} =\frac{50*30}{150}=10$

And the expected values are given by:

NyQuil Robitussin Triaminic Total

No relief 11 11 11 33

Some relief 29 29 29 87

Total relief 10 10 10 30

Total 50 50 50 150

And now we can calculate the statistic:

$\chi^2 = \frac{(11-11)^2}{11}+\frac{(13-11)^2}{11}+\frac{(9-11)^2}{11}+\frac{(32-29)^2}{29}+\frac{(28-29)^2}{29}+\frac{(27-29)^2}{29}+\frac{(7-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(14-10)^2}{10} =3.81$

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(3-1)(3-1)=4$

And we can calculate the p value given by:

$p_v = P(\chi^2_{4,0.05} >3.81)=0.43233$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(3.81,4,TRUE)"

Since the p values is higher than the significance level we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we don't have significant differences between the 3 remedies analyzed.

4 0

3 years ago