(NH4)3PO4 :
N = 14 * 3 = 42
H = 1 * 12 = 12
P = 31 * 1 = 31
O = 16 * 4 = 64
-------------------------
42+12+31+64 = 149 g / mol
Hope this helps!.
Explanation:
A nuclear fission reaction is defined as the reaction in which a heavy nucleus splits into small nuclei along with release of energy.
The given reaction is 
Now, we balance the mass on both reactant and product side as follows.
235 + 1 =
236 = 234 + x
x = 236 -234
= 2
So, now we balance the charge on both reactant and product side as follows.
92 + 0 = 
92 = 96 - y
y = 4
Thus, we can conclude that there are 2 neutrons and 4 beta-particles are produced in the given reaction.
Therefore, reaction equation will be as follows.

Answer:
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<span>Reaction of ethane combustion:
2C2H6 (g) + 7O2 (g) ----> 4CO2 (g) + 6H2O
According to the reaction, we can see that </span>C2H6 and CO2 have following stoichiometric ratio:
n(C2H6) : n(CO2) = 2 : 4
If we know the number of moles of ethane we can calculate moles of carbon dioxide:
2 x n(CO2) = 4 x n(C2H6)
n(CO2) = 2 x n(C2H6)
n(CO2) = 2 x 5.4 = 10.8 mole of CO2 <span>are produced</span>