When 2 electric charges are place close to each other they experience a force between them. This force may be repulsive or attractive depending on the type of charges involved.
The magnitude of this force depend on the quantity of individual charges and the distance between them.
The force is defined by the <em>Coulomb's law</em> states that: <em>The magnitude of the electrostatic force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them.</em>
The formula for calculating the force between 2 electric charges is ;
F = (kq₁q₂)/d²
Where k is the proportionality constant known as Coulomb's constant,
q₁ and q₂ are the charges and
d is the distance between q₁ and q₂.
B) Irregular
Good luck on the rest :D
Qs 1: Yes, there is a force, and distance, and they point in the same direction.
Qs 2: 420,000 J
Answer:
Option 2 is the correct answer.
Explanation:
We have equation of motion s = ut + 0.5at²
Here u = 0 m/s
So, s = 0.5at²
Distance traveled in first second = 0.5 x a x 1² = 0.5 a
Distance traveled in second second = 0.5 x a x 2² - 0.5 x a x 1²= 1.5 a
Distance traveled in third second = 0.5 x a x 3² - 0.5 x a x 2²= 2.5 a
Distance traveled in fourth second = 0.5 x a x 4² - 0.5 x a x 3²= 3.5 a
The percentage increase in its displacement during the 4th second compared to its displacement in the 3rd second
Option 2 is the correct answer.