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bagirrra123 [75]
4 years ago
6

A stealth bomber is flying straight and level at a constant speed of 150 m/s at an altitude of 3500 m above the ground. It drops

a bomb intended to hit a specific target on the ground.
a) How long will it take for the bomb to hit the ground?

b) At what horizontal distance away from its target must the bomber release the bomb in order to strike its target?

**disregard air resistance**
Physics
1 answer:
dangina [55]4 years ago
5 0
Height = \frac{1}{2} gt^2 \\ \\ 3500 = \frac{1}{2} (9.8)(t^2)\\ \\3500 = 4.9t^2\\\\t^2 =714.285714286\\\\\boxed {t=26.73~seconds}



\sf Horizontal ~distance = velocity \times time\\\\ Horizontal distance =150 \times 26.73 \\\\Horizontal ~distance =4009.5
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F=10\times 9.8=98\ kg

change in length is given by

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Where A=area of cross-section

A=\dfrac{Pl}{\Delta lE}

A=\dfrac{98\times 0.75}{1.85\times 10^{-3}\times 7.9\times 10^{10}}

A=\dfrac{73.5}{14.615\times 10^{7}}

A=5.029\times 10^{-7}\ m^2

also wire is the shape of cylinder so cross-section is given by

A=\dfrac{\pi d^2}{4}=5.029\times 10^{-7}\ m^2

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\Rightarrow d^2=64.02\times 10^{-8}

\Rightarrow d=8\times 10^{-4}\ m

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