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Eddi Din [679]
3 years ago
12

In a reaction process a company expected to make 6.8

Chemistry
1 answer:
svetlana [45]3 years ago
3 0

Answer:

1) 61.8%

Explanation:

(4.2/6.8)*100

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Calculate the freezing point of a solution containing 15 grams of kcl and 1650.0 grams of water. the molal-freezing-point-depres
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Answer is: freezing point is -0,226°C.
Answer is: the molal concentration of glucose in this solution is 1,478 m.
m(KCl) = 15 g.
n(KCl) = m(KCl) ÷ M(KCl).
n(KCl) = 15 g ÷ 74,55 g/mol.
n(KCl) = 0,2 mol
m(H₂O) = 1650 g ÷ 1000 g/kg = 1,65 kg.
b = n(KCl) ÷ m(H₂O).
b = 0,2 mol ÷ 1,65 kg = 0,122 m.
Kf(water) = 1,86°C/m.
ΔT = Kf(water) · b(solution).
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ΔT = 0,226°C.
4 0
3 years ago
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2. Can oxidation occur without reduction? Explain.
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4 0
3 years ago
How do electrostatic forces affect the electrons in an atom?
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The answer is C.
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What type of chemical reaction is this?
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Use the conversion factor 1amu=6.66054 x 10^-24 to answer the following questions.. . a) 1.674 x 10^-24 g of neutrons is how man
Wewaii [24]
A.) The conversion factor is 1 amu = 1.66054 ^{-24}g

To know how many amu in 1.674x10^{-24}g grams of neutrons:
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6.492x10^{-23}g ( \frac{x (amu) }{ 1.66054x10^{-24}g }) = 39.0957 amu


6 0
3 years ago
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