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DedPeter [7]
3 years ago
6

Helppppppppppp!!!!!!!!

Chemistry
1 answer:
Natali5045456 [20]3 years ago
8 0

Pressure does not affect the voltage produced in a voltaic cell.

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2. For the reaction, 2SO2(g) + O2(g) 2SO3(g), at 450.0 K the equilibrium con¬stant, Kc, has a value of 4.62. A system was charge
miv72 [106K]

Answer:

Q >> Kc

We have more products than reactans. To reach the equilibrium, the balance will shift to the left.

Explanation:

Step 1: Data given

Temperature = 450.0 K

Kc = 4.62

When Kc > Q, we have more reactants than products. To reach the equilibrium, the balance will shift to the right

When Kc < Q, we have more products than reactans. To reach the equilibrium, the balance will shift to the left.

When Kc = Q,the equiation isatequilibrium

[SO3] = 0.254 M

[O2] = 0.00855 M

[SO2] = 0.500 M

Step 2: The balanced equation

2SO2(g) + O2(g) ⇄ 2SO3(g)

Step 3: Calculate the Q

Q = [SO3]² / [O2][SO2]²

Q = 0.254²/ (0.500 * 0.00855²)

Q = 1765

Q >> Kc

We have more products than reactans. To reach the equilibrium, the balance will shift to the left.

6 0
4 years ago
Read 2 more answers
Calculate the ΔH o for the reaction: Fe3+(aq) + 3OH−(aq) → Fe(OH)3(s) ΔH o = kJ/mol Substance ΔH o f (kJ/mol) ΔG o f (kJ/mol) S
timofeeve [1]

Answer:

ΔHr = -86.73 kJ/mol

Explanation:

Using Hess's law, you can calculate ΔH of any reaction using ΔH°f of products and reactants involed in the reaction.

<em>Hess law: ∑nΔH°f products - ∑nΔH°f reactants = ΔHr</em>

<em>-Where n are moles of reaction-</em>

For the reaction:

Fe³⁺(aq) + 3 OH⁻(aq) → Fe(OH)₃(s)

Hess law is:

ΔHr = ΔH°f Fe(OH)₃ - ΔH°f Fe³⁺ - 3×ΔH°f OH⁻

Where:

ΔH°f Fe(OH)₃: −824.25 kJ/mol

ΔH°f Fe³⁺: −47.7 kJ/mol

ΔH°f OH⁻: −229.94 kJ/mol

Replacing:

ΔHr = −824.25 kJ/mol - (−47.7 kJ/mol) - (3×-229.94 kJ/mol)

<em>ΔHr = -86.73 kJ/mol</em>

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Five strategies needed by learners to acquire knowledge and skills to make informed decisions and take appropriate actions to en
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What is ammonification?
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