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3 years ago

What’s the area of this? i really need help....50 points if u help me :)

Mathematics

1 answer:

Aleksandr-060686 [28]3 years ago

5 0

Answer:

Step-by-step explanation:

We can split this up into 3 shapes.

Using the attached image:

$A = (5-2)*(3)\\A = 3*3 = 9\\\\B = \frac{1}{2}(7-3)(5-2)\\B = \frac{1}{2}(4)(3)\\B = 2*3 = 6\\\\C = 7 * 2 = 14\\\\A + B + C = 14 + 6 + 9 = 29$

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White raven [17]

Answer:

A is the only solution.

Step-by-step explanation:

A simple way to solve it is to plug in the x and y values

For A, we plug in 2 for x and 3 for y

3-3=5(2-2)

0=5(0)

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Ordered pair A is a solution

For B, plug in 3 for x and 2 for y

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Therefore only A is a solution

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3 years ago

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torisob [31]

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3 years ago

9. Write quadratic function with zeros 3, 6

Dmitry_Shevchenko [17]

Answer:

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Step-by-step explanation:

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3 years ago

In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.

jekas [21]

Answer:

1,805 kg.

Step-by-step explanation:

We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.

First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.

$\text{The weight of average pumpkin}=\frac{5000\text{ gm}}{\frac{\text{1000 gm}}{\text{ 1 kg}}}$

$\text{The weight of average pumpkin}=5000\text{ gm}\times \frac{\text{ 1 kg}}{\text{1000 gm}}$

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Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

$1,810\text{ kilograms}-5\text{ kilograms}=1,805\text{ kilograms}$

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.

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4 years ago

Read 2 more answers