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balandron [24]
2 years ago
13

What’s the area of this? i really need help....50 points if u help me :)

Mathematics
1 answer:
Aleksandr-060686 [28]2 years ago
5 0

Answer:

Step-by-step explanation:

We can split this up into 3 shapes.

Using the attached image:

A = (5-2)*(3)\\A = 3*3 = 9\\\\B = \frac{1}{2}(7-3)(5-2)\\B = \frac{1}{2}(4)(3)\\B = 2*3 = 6\\\\C = 7 * 2 = 14\\\\A + B + C  = 14 + 6 + 9 = 29

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cricket20 [7]
An odd number ends in 1, 3, 5, 7, or 9.
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3 years ago
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Which of the following ordered pairs represents the solution to the system of equations below?
expeople1 [14]
<span>-3x + 2y = 2  eq (1)

  7x - 3y = 7    eq (2)

Mutiply eq (1) by 3 and eq (2) by 2:

-9x + 6y = 6

14x - 6y = 14

Add th two new equations:

-9x + 14x = 6 + 14

=> 5x = 20

=> x = 20/5

=> x = 4

Now from eq (1)

-3(4) + 2y = 2

=> 2y = 2 + 12

=> 2y = 14

=> y = 14 / 2

=> y = 7

So the ordered pair is (4,7)

Answer: option B. (4,7)
</span>
5 0
3 years ago
How to do this ??????
sergeinik [125]

the answer would be a or b. Turn on verified mode for professionals to answer)

8 0
2 years ago
I have a strange True or False question on my packet.. But here I go: "A trapezoid has two 90 degree angles." Is it true or fals
alex41 [277]

Answer:

False unless a right trapezoid.

Step-by-step explanation:

All trapezoids have 4 angles which add to 360 degrees. The angles can be any measure except in a right trapezoid which does have two 90 degree angles. It is not a requirement to be a trapezoid though so this is false.

8 0
3 years ago
A university is trying to determine what price to charge for tickets to football games. At a price of ​$ per​ ticket, attendance
Anika [276]

This question is incomplete, the complete question is;

A university is trying to determine what price to charge for tickets to football games. At a price of ​$24 per​ ticket, attendance averages 40,000 people per game. Every decrease of ​$4 adds 10,000 people to the average number. Every person at the game spends an average of ​$4 on concessions. What price per ticket should be charged in order to maximize​ revenue? How many people will attend at that​ price?

Answer:

a) price per ticket = $18

b) 55,000 will attend at that price

Step-by-step explanation:

Given that;

price of ticket = $24

so cost of ticket = 24 - x

every decrease of $4 adds 10,000 people

for $1 adds 2,500 people

Total people = 40000 + 2500x

Revenue function = people × cost + people × 4

so

R(x) = (40000 + 2500x)(24 - x) + (40000 + 2500x)4

R(x) = 960,000 - 40000x + 60000x - 2500x² + 160,000 + 10000x

R(x) = 1120000 + 30000x - 2500x²

R(x) = -2500x² + 30000x + 1120000

now for maximum revenue; R'(x) is to zero

so

R'(x) = d/dx(  -2500x² + 30000x + 1120000 ) = 0

⇒ -5000x + 30000 + 0 = 0

⇒ -5000x + 30000 = 0

⇒ 5000x = 30000

x = 30000 / 5000

x = 6

R'(X) = -5000 < 0 ⇒ MAXIMUM

∴ Revenue is maximum at x = 6

so cost of ticket ;

price per ticket = (24 - x) = 24 - 6 = $18

so price per ticket = $18

Number of people = 40000 + 2500x

= 40000 + (2500 × 6)

= 40000 + 15,000

= 55,000

Therefore, 55,000 will attend at that price

8 0
2 years ago
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