Answer:
Objects that float on water have densities less than the density of water; those that do not float on water have densisties greater than the density of water:
Float on water: d < 0.0361 lb/in³ (where d denotes denisity)
Do not float on water: d > 0.0361 lb/in³
Explanation:
I don't know if this works for it or not?
Answer:
Q = 86.38 gpm
Explanation:
pressure in house = 135 psig
1 psig = 6894.76 pa
= 135 × 6894.76 pa = 930792 pa
P = ρ g h
h = 94.88 m
velocity at the exit of nozzle
discharge (Q) = Av
=
=
Q = 86.38 gpm
Answer:
Z = 3 + 0.23t
The water level is rising
Explanation:
Please see attachment for the equation
Answer:
F = 33,324,295.32N
Explanation:
We will first of all find the height at which the plate is inclined. We use sine rule in this case
SinΘ = Opp/hyp
Opp=h, hyp=19m, Θ=35°
h = 19xSin35 = 10.899m
Therefore height h=10.899+4 = 14.899m
We then Calculate Area of the plate
Area = 12x19 = 228m²
Finally, we use an online software to calculate the Hydrostatic pressure
The result from the online computation is attached.
The pressure is p = 146159.19Pa
But pressure p is
Pressure=Force/Area
Making Force the subject
Hydrostatic Force = Pressure x Area
F= 146159.19 x 228 = 33,324,295.32N
F = 33,324,295.32N
Answer:
From the question, we have two variables
1. userNum1
2. userNum2
And we are to print "userNum1 is negative" if userNum1 is less than 0.
Then Assign userNum2 with 2 if userNum2 is greater than 10.
Otherwise, print "userNum2 is less or equal 10.".
// Program is written in C++ Programming Language
// Comments are used for explanatory purpose
// Program starts here
#include<iostream>
using namespace std;
int main ()
{
// Declare variables
int userNum1, userNum2;
// Accept input for these variables
cin>>userNum1, userNum2;
// Condition 1
if(userNum1 < 0)
{
cout<<"userNum1 is negative"<<'\n';
}
// Condition 2
if(userNum2 > 10)
{
userNum2 = 2;
}
// If condition is less than 10
else
{
cout<<"userNum2 is less or equal to 10"<<\n;
}
return 0;
}
// End of Program.