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3 years ago

El protozoos es del reino protista?

Engineering

2 answers:

poizon [28]3 years ago

5 0

Answer:

Protozoario o protozoo es un organismo unicelular y eucariota (con núcleo celular definido) perteneciente al Reino protista. Los protozoarios se encuentran junto con los protófitos o algas simples, generalmente acuáticas, dentro del Reino protista o también denominado Reino protoctista.

Explanation:

iogann1982 [59]3 years ago

3 0

Answer: Si (Yes)

Explanation:

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A pipe leads from a storage tank on the roof of a building to the ground floor. The absolute pressure of the water in the storag

Fudgin [204]

Answer:

6.4 m/s

Explanation:

From the equation of continuity

A1V1=A2V2 where A1 and V1 are area and velocity of inlet respectively while A2 and V2 are the area and velocity of outlet respectively

$A1=\pi (r1)^{2}$

$A2=\pi (r2)^{2}$

where r1 and r2 are radius of inlet and outlet respectively

v1 is given as 1.6 m/s

Therefore

$\pi (0.01)^{2}\times 1.6 = \pi (0.005)^{2}v2$

$V2=\frac {\pi (0.01)^{2}\times 1.6}{\pi (0.005)^{2}}=6.4 m/s$

3 0

4 years ago

WHAT IS A VACUOMETER?

Alex_Xolod [135]

It is a tool used to measure Low pressure

4 0

3 years ago

Read 2 more answers

The volume of 1.5 kg of helium in a frictionless piston-cylinder device is initially 6 m3. Now, helium is compressed to 2 m3 whi

coldgirl [10]

Answer:

The initial temperature will be "385.1°K" as well as final will be "128.3°K".

Explanation:

The given values are:

Helium's initial volume, v₁ = 6 m³

Mass, m = 1.5 kg

Final volume, v₂ = 2 m³

Pressure, P = 200 kPa

As we know,

Work, $W=p(v_{2}-v_{1})$

On putting the estimated values, we get

⇒ $=200000(2-6)$

⇒ $=200000\times (-4)$

⇒ $=800,000 \ N.m$

Now,

Gas ideal equation will be:

⇒ $pv_{1}=mRT_{1}$

On putting the values. we get

⇒ $200000\times 6=1.5\times 2077\times T_{1}$

⇒ $T_{1}=\frac{1200000}{3115.5}$

⇒ $=385.1^{\circ}K$ (Initial temperature of helium)

and,

⇒ $pv_{2}=mRT_{2}$

On putting the values, we get

⇒ $200000\times 2=1.5\times 2077\times T_{2}$

⇒ $T_{2}=\frac{400000}{3115.5}$

⇒ $=128.3^{\circ}K$ (Final temperature of helium)

3 0

3 years ago

A manager has a list of items that have been sorted according to an item ID. Some of them are duplicates. She wants to add a cod

ruslelena [56]

Answer:

The solution code is written in Python:

items = [{"id": 37697, "code": ""},{"id": 37698, "code": ""},{"id": 37699, "code": ""},{"id": 37699, "code": ""}, {"id": 37699, "code": ""},
{"id": 37699, "code": ""},{"id": 37699, "code": ""},{"id": 37699, "code": ""},{"id": 37700, "code": ""} ]
items[0]["code"] = 1
for i in range(1, len(items)):
if(items[i]["id"] == items[i-1]["id"]):
items[i]["code"] = items[i-1]["code"] + 1
else:
items[i]["code"] = 1
print(items)

Explanation:

Firstly, let's create a list of dictionary objects. Each object holds an id and a code (Line 1-2). Please note all the code is initialized with zero at the first beginning.

Next, we can assign 1 to the code property of items[0] (Line 4).

Next, we traverse through the items list started from the second element (Line 6). We set an if condition to check if the current item's id is equal to the previous item (Line 7). If so, we assign the previous item's code + 1 to the current item's code (Line 8). If not, we assign 1 to the current item's code (Line 10).

At last, we print out the item (Line 12) and we shall get

[{'id': 37697, 'code': 1}, {'id': 37698, 'code': 1}, {'id': 37699, 'code': 1}, {'id': 37699, 'code': 2}, {'id': 37699, 'code': 3}, {'id': 37699, 'code': 4}, {'id': 37699, 'code': 5}, {'id': 37699, 'code': 6}, {'id': 37700, 'code': 1}]

6 0

4 years ago

a television set having apower rating of 120w and electric lawnmower of power rating 1kw are both connected to a 250v supply if

Soloha48 [4]

Answer:

Television

Power = 120 w

p.d = 240 v

I = p / v

I = 120 / 240 = 0.5

Fuse can be used 3A

lawnmower

Power = 1000w

p.d = 240 v

I = 1000/ 240 = 4.16

Fuse can be used = 5A

8 0

3 years ago