A rectangular plate with a width of 19 m and a height of 12 m is located 4 m below a water surface. The plate is tilted and make
s a 35° angle with the horizontal. The resultant hydrostatic force acting on the top surface of this plate is _____. Solve this problem using appropriate software.
1 answer:
Answer:
F = 33,324,295.32N
Explanation:
We will first of all find the height at which the plate is inclined. We use sine rule in this case
SinΘ = Opp/hyp
Opp=h, hyp=19m, Θ=35°
h = 19xSin35 = 10.899m
Therefore height h=10.899+4 = 14.899m
We then Calculate Area of the plate
Area = 12x19 = 228m²
Finally, we use an online software to calculate the Hydrostatic pressure
The result from the online computation is attached.
The pressure is p = 146159.19Pa
But pressure p is
Pressure=Force/Area
Making Force the subject
Hydrostatic Force = Pressure x Area
F= 146159.19 x 228 = 33,324,295.32N
F = 33,324,295.32N
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Answer:
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Explanation:
The formula to apply here is ;
K=(d²-d²₀ )/t
where t is time in hours
d is grain diameter to be achieved after heating in mm
d₀ is the grain diameter before heating in mm
Given
d=5.5 × 10^-2 mm
d₀=2.4 × 10^-2 mm
t₁= 500 min = 500/60 =25/3 hrs
t₂=?
n=2.2
First find K
K=(d²-d²₀ )/t₁
K={ (5.1 × 10^-2 mm)²-(2.4 × 10−2 mm)² }/ 25/3
K=(0.051²-0.024²) ÷25/2
K=0.000243 mm²/h
Re-arrange equation for K ,to get the equation for d as;
d=√(d₀²+ Kt) where now t=t₂
Answer:
230.4W
Explanation:
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the equation is as follows
Where
Q=heat
k=conductivity=0.04
A=Area=1.8m^2
T2=33C
T1=1C
L=thickness=1cm=0.01m
Q=230.4W
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