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pshichka [43]
3 years ago
13

A rectangular plate with a width of 19 m and a height of 12 m is located 4 m below a water surface. The plate is tilted and make

s a 35° angle with the horizontal. The resultant hydrostatic force acting on the top surface of this plate is _____. Solve this problem using appropriate software.

Engineering
1 answer:
Kruka [31]3 years ago
4 0

Answer:

F = 33,324,295.32N

Explanation:

We will first of all find the height at which the plate is inclined. We use sine rule in this case

SinΘ = Opp/hyp

Opp=h, hyp=19m, Θ=35°

h = 19xSin35 = 10.899m

Therefore height h=10.899+4 = 14.899m

We then Calculate Area of the plate

Area = 12x19 = 228m²

Finally, we use an online software to calculate the Hydrostatic pressure

The result from the online computation is attached.

The pressure is p = 146159.19Pa

But pressure p is

Pressure=Force/Area

Making Force the subject

Hydrostatic Force = Pressure x Area

F= 146159.19 x 228 = 33,324,295.32N

F = 33,324,295.32N

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Answer:153.76 MPa

Explanation:

Initial Area\left ( A_0\right )=12.56 mm^2

Final Area\left ( A_f\right )=0.7\times 12.56 mm^2=8.792 mm^2

Die angle=30^{\circ}

\alpha =\frac{30}{2}=15^{\circ}

\mu =0.08

Yield stress\left ( \sigma _y \right )=350 MPa

B=\mu cot\left ( \aplha\right )=0.2985

\sigma _{pressure}=\sigma _y\left [\frac{1+B}{B}\right ]\left [ 1-\frac{A_f}{A_0}\right ]^B

\sigma _{pressure}=350\left [\frac{1+0.2985}{0.2985}\right ]\left [ 1-\frac{8.792}{12.56}\right ]^{0.2985}

\sigma _{pressure}=153.76 MPa

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2 years ago
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T_{1} = 27^{o}C = (27 + 273) K = 300 K

We know that for an ideal gas the mass flow rate will be calculated as follows.

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Now, according to the steady flow energy equation:

mh_{1} + Q = mh_{2} + W

h_{1} + \frac{Q}{m} = h_{2} + \frac{W}{m}

C_{p}T_{1} - \frac{80}{10} = C_{p}T_{2} - \frac{130}{10}

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T_{2} = 5 K + 300 K

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If you measure 0.7 V across a diode, the diode is probably therefore made of Silicon.

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