Hi,
Domain of (fog)(x) is R \ {13} =(-oo 13[ U ]13 +oo)
Hello :
<span>C.) (4 · 4) – (4 ÷ 4) =16-1=15</span>
<h2>
Translating Sentences into Equations</h2>
A key part of this is recognizing certain words to change into operations or numbers:
- <em>quotient</em> = divide
- <em>three more</em> = add 3
- <em>'a/the number' </em>= use a variable (in this case, it's <em>w</em>)
<h2>Solving the Question</h2>
We're given:
- Three more than the quotient of a number and 7 equals 6
⇒ 'the quotient of a number and 7' tells us we divide <em>w</em> by 7: - Three more than
equals 6
⇒ 'three more than' means we add 3 to the fraction: 
equals 6
<h2>Answer</h2>
Consecutive integers are 1 apart
x,x+1,x+2
(x)(x+1)(x+2)=-120
x^3+3x^2+3x=-120
add 120 to both sides
x^3+3x^2+3x+120=0
factor
(x+6)(x^2-3x+20)=0
set each to zero
x+6=0
x=-6
x^2-3x+20=0
will yeild non-real result, discard
x=-6
x+1=-5
x+2=-4
the numbers are -4,-5,-6
use trial and error and logic
factor 120
120=2*2*2*3*5
how can we rearange these numbers in (x)(y)(z) format such that they multiply to 120?
obviously, the 5 has to stay since 2*5=10 which is out of range
so 2*2*2*3 has to arrange to get 3,4 or 4, 6 or 6,7
obviously, 7 cannot happen since it is prime
3 and 4 results in in 12, but 2*2*2*3=24
therfor answer is 4 and 6
they are all negative since negaive cancel except 1
the numbers are -4,-5,-6
We would have
a + b = 360
a - 40 = b, so we solve as follows:
360-40=320,
320/2 = 160,
160 + 40 = 200.
Check: 200+160 = 360, so
200 is your answer.
Hope this helps and have a nice day:)
