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3 years ago

What causes the different colors of visible light in the electromagnetic spectrum?

Physics

1 answer:

liraira [26]3 years ago

5 0

Answer:

The color of the light is determined by the frequency of the light wave. Red, is lowest, frequency and violet is the highest.

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Magnets are created due to the uniform motion of

Alinara [238K]

<span>Magnets are created due to the uniform motion of "Electrons"

Hope this helps!</span>

7 0

3 years ago

Read 2 more answers

Three identical capacitors are connected in series across a potential source (battery). If a charge of Q flows into this combina

inessss [21]

Answer:

C.Q/3

Explanation:

The total capacitances in series

1/C=1/C1+1/C2+1/C3

=1 /C+1/C+1/C

3/C

Ctotal=C/3

Charge in each capacitances

1/3*Q

Q/3

8 0

3 years ago

A spacecraft in the shape of a long cylinder has a length of 100 m, and its mass with occupants is 1 480 kg. It has strayed too

maks197457 [2]

Answer:

2352645198509.9604 m/s²

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of black hole = $90\times 1.989\times 10^{30}\ kg$

$R_{f}$ = 10000+100 m

$R_{sb}$ = Distance between the nose and the center of the black hole = 10000 m

The difference in the gravitational field in this system is given by

$\Delta F=\dfrac{GMm}{R_{f}^2}-\dfrac{GMm}{R_{sb}^2}\\\Rightarrow \Delta g=GM\left(\frac{1}{R_f^2}-\frac{1}{R_{sb}^2}\right)\\\Rightarrow g=6.67\times 10^{-11}\times 90\times 1.989\times 10^{30}\left(\frac{1}{(10000+100)^2}-\frac{1}{10000^2}\right)\\\Rightarrow \Delta g=-2352645198509.9604\ m/s^2$

The acceleration is 2352645198509.9604 m/s²

4 0

3 years ago

When a potential difference of 12 v is applied to a wire 6.8 m long and 0.35 mm in diameter the result is an electric current of

Nonamiya [84]

The total resistance is R = voltage / current

This resistance R = (L/A)r where:
r is the resistivity
L is the length of the conductor
A is the cross-sectional area of the conductor.

thus r = RA/L

You are given L; you can compute R from the voltage and current you are given; and the cross-sectional area of a round wire is (pi)(radius^2) or (pi/4)(diameter^2)

8 0

3 years ago

A point charge with a charge q1 = 2.30 μC is held stationary at the origin. A second point charge with a charge q2 = -5.00 μC mo

Alla [95]

Answer:

W = 2.74 J

Explanation:

The work done by the charge on the origin to the moving charge is equal to the difference in the potential energy of the charges.

This is the electrostatic equivalent of the work-energy theorem.

$W = \Delta U = U_2 - U_1$

where the potential energy is defined as follows

$U = \frac{1}{4\pi\epsilon_0}\frac{q_1q_2}{r^2}$

Let's first calculate the distance 'r' for both positions.

$r_1 = \sqrt{(x_1 - x_0)^2 + (y_1 - y_0)^2} = \sqrt{(0.170 - 0)^2 + (0 - 0)^2} = 0.170~m\\r_2 = \sqrt{(x_2 - x_0)^2 + (y_2 - y_0)^2} = \sqrt{(0.250 - 0)^2 + (0.250 - 0)^2} = 0.353~m$

Now, we can calculate the potential energies for both positions.

$U_1 = \frac{kq_1q_2}{r_1^2} = \frac{(8.99\times 10^9)(2.3\times 10^{-6})(-5\times 10^{-6})}{(0.170)^2} = -3.57~J\\U_2 = \frac{kq_1q_2}{r_2^2} = \frac{(8.99\times 10^9)(2.3\times 10^{-6})(-5\times 10^{-6})}{(0.3530)^2} = -0.829~J$

Finally, the total work done on the moving particle can be calculated.

$W = U_2 - U_1 = (-0.829) - (-3.57) = 2.74~J$

4 0

3 years ago

Read 2 more answers