In the system shown above, the pulley is a uniform disk with a mass of .75 kg and a radius of 6.5 cm. The coefficient of frictio
n between the 5.8 kg mass and the horizontal surface is .25, and the ropes does not slip on the pulley. They system is released from rest. Use work-energy principles to determine the kinetic energy of the (a) 2.8 kg mass and (b) the pulley after the 5.8 kg mass has moved 2.2 meters.
1 answer:
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Answer:
The average linear velocity (inches/second) of the golf club is 136.01 inches/second
Explanation:
Given;
length of the club, L = 29 inches
rotation angle, θ = 215⁰
time of motion, t = 0.8 s
The angular speed of the club is calculated as follows;
The average linear velocity (inches/second) of the golf club is calculated as;
v = ωr
v = 4.69 rad/s x 29 inches
v = 136.01 inches/second
Therefore, the average linear velocity (inches/second) of the golf club is 136.01 inches/second
Answer:
Velocity = 0.105m/s
Explanation:
Using conservation of momentum:
Momentum before impact= mass of ball × velocity of ball
= 0.400×10.8= 4.32
Momentum after impart= mass of ball × velocity of ball + mass of olaf × velocity of olaf
= 4.35 +3.56 + 74.9Vf
Vf=7.88_74.9 = o.0.105m/s
