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masha68 [24]
2 years ago
10

A golf club rotates 215 degrees and has a length (radius) equal to 29 inches. The time it took to swing the club was 0.8 seconds

. What is the average linear velocity (inches/second) of the golf club
Physics
1 answer:
vichka [17]2 years ago
8 0

Answer:

The average linear velocity (inches/second) of the golf club is 136.01 inches/second

Explanation:

Given;

length of the club, L = 29 inches

rotation angle, θ = 215⁰

time of motion, t = 0.8 s

The angular speed of the club is calculated as follows;

\omega = (\frac{\theta}{360} \times 2\pi, \ rad) \times \frac{1}{t} \\\\\omega =  (\frac{215}{360} \times 2\pi, \ rad) \times \frac{1}{0.8 \ s} \\\\\omega = 4.69 \ rad/s

The average linear velocity (inches/second) of the golf club is calculated as;

v = ωr

v = 4.69 rad/s  x  29 inches

v = 136.01 inches/second

Therefore, the average linear velocity (inches/second) of the golf club is 136.01 inches/second

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Correct question:

A radio transmitting station operating at a frequency of 120 MHz has two identical antennas that radiate in phase. Antenna B is 9.05 m to the right of antenna A. Consider point P between the antennas and along the line connecting them, a horizontal distance x to the right of antenna A.

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Given;

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make a sketch of this antenna

A-------------------P------------------B

         x                      9.05 - x

Now, we calculate the wavefront between the two antenna

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the path difference = constructive interference

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x = 4.525 - n(1.25)

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x = 4.525 + 1(1.25)

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x = 4.525 + 2(1.25)

x = 7.025m

when n = -3

x = 4.525 + 3(1.25)

x = 8.275m

when n = 0

x = 4.525 - 0(1.25)

x = 4.525m

when n = 1

x = 4.525 - 1(1.25)

x = 3.275m

when n = 2

x = 4.525 - 2(1.25)

x = 2.025m

when n = 3

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x = 0.775m

Thus, values of x in which constructive interference will occur at point P are; 0.775 m, 2.025 m, 3.275 m, 4.525 m, 5.775 m, 7.025 m, 8.275 m

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