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3 years ago

Will reward brainliest

Chemistry

2 answers:

Kazeer [188]3 years ago

6 0

<span>Stratosphere. ...Mesosphere. ...Thermosphere. ...Ionosphere. ...<span>Exosphere.</span></span>

Ratling [72]3 years ago

3 0

Answer:

crust

mantle

Outer Core

Inner Core

Atmosphere

Explanation:

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anuvia, the trade name for sitagliptin, was introduced in 2006 for the treatment of type 2 diabetes. In what type of orbital doe

Aleonysh [2.5K]

Answer: hello your question is poorly written below is the complete question

answer:

For N1 : sp³ orbital

For N2: p orbital

For N3 : p orbital

For N4 : sp² orbital

For N5 : sp² orbital

Explanation:

Determining the type of orbital in which the lone pair on each N atom will reside.

From the configuration attached below we can determine the type of orbital and they are ;

For N1 : sp³ orbital

For N2: p orbital

For N3 : p orbital

For N4 : sp² orbital

For N5 : sp² orbital

5 0

2 years ago

2N2 + 3H2 → 2NH3

denis23 [38]

There are two N≡N bonds and three H–H bonds are in reactants.

Given:

The reaction between nitrogen gas and hydrogen gas.

$2N_2+3H_2\rightarrow 2NH_3$

To find:

Bonds on the reactant side

Solution:

$2N_2+3H_2\rightarrow 2NH_3$

Reactants in the reaction = $N_2, H_2$

The bond between nitrogen atoms in single $N_2$ molecule = N≡N (triple bond)

Then in two $N_2$ molecules = 2 N≡N (triple bonds)

The bond between hydrogen atoms in single $H_2$ molecule = H-H (single bond)

Then in three $H_2$ molecules = 3 H-H (single bonds)

Product in the reaction = $NH_3$

The bonds between nitrogen and hydrogen atoms in single $NH_3$ molecule = 3 N-H (single bond)

Then in two $NH_3$ molecules = 6 N-H (single bonds)

So, there are two N≡N bonds and three H–H bonds are in reactants.

Learn more about reactants and products here:

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3 0

2 years ago

Phosphoric acid, which is commonly used as rust inhibitor, food additive and etching agent for dental and orthopedic use, can be

Sphinxa [80]

Answer:

$P_4_{(I)}+5O_2_{(g)}+6H_2O_{(l)}\rightarrow +4H_3PO_4_{(l)}$

Explanation:

The first step is:

$P_4_{(I)}+5O_2_{(g)}\rightarrow 2P_2O_5_{(g)}$

Second step is:

$P_2O_5_{(g)}+3H_2O_{(l)}\rightarrow 2H_3PO_4_{(l)}$

Multiplying second step by 2, and adding both the steps, we get that:

$P_4_{(I)}+5O_2_{(g)}+2P_2O_5_{(g)}+6H_2O_{(l)}\rightarrow 2P_2O_5_{(g)}+4H_3PO_4_{(l)}$

Cancelling common species, we get that:

$P_4_{(l)}+5O_2_{(g)}+6H_2O_{(l)}\rightarrow +4H_3PO_4_{(l)}$

6 0

3 years ago

Consider the reaction of CaCN2 and water to produce CaCO3 and NH3 according to the reaction CaCN2 + 3H2O → CaCO3 + 2 NH3 . How m

adelina 88 [10]

Answer:

56 g. Option 3.

Explanation:

The reaction is: CaCN₂ + 3H₂O → CaCO₃ + 2 NH₃

1 mol of calcium cianide reacts with 3 moles of water in order to produce 1 mol of calcium carbonate and 2 moles of ammonia

We have the mass of each reactant, so let's convert the mass to moles:

45 g. 1mol / 80.08 g = 0.562 moles of cianide

45 g. 1mol / 18 g = 2.5 moles of water

The cianide is the limiting reactant:

3 moles of water need 1 mol of cianide to react

Then, 2.5 moles of water will need (2.5 . 1)/ 3 = 0.833 moles

As we have 0.562 moles of CN⁻ we don't have enough

We can work now, on the reaction:

Ratio is 1:1. Therefore 0.562 moles of cianide will produce 0.562 moles of carbonate

Let's convert the mass to moles to find the answer:

0.562 mol . 100.08 g / 1 mol = 56.2 g

8 0

3 years ago

Why is an alkali metal element like sodium (Na) so reactive?

guapka [62]

Alkali metals are known for being some of the most reactive metals. This is due in part to their larger atomic radii and low ionization energies. They tend to donate their electrons in reactions and often have an oxidation state of +1. These metals are characterized as being extre

3 0

3 years ago