Answer:
The vapor pressure of ethanol in the solution is 10,27 kPa
Explanation:
To obtain the vapor pressure of a solution it is necessary to use Raoult's law:
<em>(1)</em>
The moles of ethanol are:
18,00mL×
×
= 0,3083 mol Ethanol.
Moles of benzoic acid:
12,55 g×
= 0,1028 mol benzoic acid.
Thus, mole fraction of solvent, X, is:
=<em> 0,7499</em>
Replacing this value in (1):
= <em>10,27 kPa</em>
<em></em>
I hope it helps!
the Percentage yield for the reaction = 48.8%
What is Percentage yield ?
The % ratio of the theoretical yield to the actual yield is known as the percent yield. It is calculated as the theoretical yield multiplied by 100% divided by the experimental yield. The percent yield is 100% if the theoretical and actual yields are equal. Because the real yield is frequently lower than the theoretical value, percent yield is typically lower than 100%. This may be due to incomplete or conflicting reactions or sample loss during recovery. If the percent yield is more than 100%, more sample than expected was retrieved from the reaction.
4 P + 3 O2 = P4O6
moles P = 75.3 g / 30.9738 g/mol= 2.43
moles O2 required = 2.43 x 3 / 4=1.82
actual moles O2 = 38.7 g /32 g/mol=1.21 so O2 is the limiting reactant
theoretical moles P4O6 = 1.21 / 3=0.403
theoretical mass P4O6 = 0.403 mol x 219.895 g/mol=88.6 g
% yield = 43.3 x 100/ 88.6 = 48.8 %
the Percentage yield for the reaction = 48.8%
To know about Percentage yield from the link
brainly.com/question/8638404
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Answer:
Water - H2O
Ammonia - NH3
Sulfur dioxide - SO2
Hydrogen sulfide - H2S
Ethanol - C2H6O
Explanation:
Those are some atoms with polar covalent bonds. Hope this helps!!
Answer:
Explanation:
<u>1) Data:</u>
<u />
a) Acetic acid CH₃COOH
b) molar mass of CH₃COOH: 60.052 g/mol
c) %: = 5.00%
d) d = 1.006 g/ml
e) M = ?
<u>2) Formulae:</u>
a) M = n of solute / V of solution in liters
b) n = mass in grams / molar mass
c) % = (mass of solute / mass of solution)×100
d) d = mass / volume
<u>3) Solution:</u>
a)<u> Assume a basis </u>
b) <u>Calculate the mass of that basis (1 liter of solution)</u>
- d = mass / V ⇒ mass = d × V
- mass = 1.006 g/ml × 1 liter × 1,000 ml/liter = 1006 g
c) <u>Calculate the mass of solute</u>
<u />
- % = (mass of solute / mass of solution ) × 100 ⇒
mass of solute = % × mass of solution / 100 = 5.00% × 1,006 g / 100
mass of solute = 50.3 g
d) <u>Calculate the number of moles of solute</u>
<u />
- n = mass in grams / molar mass = 50.3 g / 60.052 g/mol = 0.838 mol
e) <u>Calculate molarity</u>
- M = n / V in liter = 0.838 mol / 1 liter = 0.838 M ← answer
Answer: 64.8
Explanation:Please see attachment for explanation