Answer:
Basic
Explanation:
Considering
So,
For hydrochloric acid :
Molarity = M
Volume = 220 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 220×10⁻³ L
Moles of hydrochloric acid = 0.000033 moles
For :
Molarity = M
Volume = 135 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 135×10⁻³ L
Moles of = 0.000024 moles
According to the given reaction:
1 mole of reacts with 2 moles of HCl
Also,
0.000024 mole of reacts with 2*0.000024 moles of HCl
Moles of HCl = 0.000048 moles
Available moles of HCl = 0.000033 moles
Limiting reagent is the one which is present in small amount. Thus, HCl is limiting reagent.
Thus, HCL will be consumed completely and will be left over. Thus, the resulting solution will be basic.
