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Serggg [28]
2 years ago
5

How many atoms are in 2.5 moles of beryllium atoms?

Chemistry
1 answer:
Irina-Kira [14]2 years ago
8 0
As we know that there are avogadro no. of atoms in 9 g of beryllium.
1 mole of beryllium = 6.02 * 10^23 atoms
so 2.5 mole= 6.02*10^23*2.5 i.e = <span>15.055 × 10^23 atoms </span>
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Answer:

Explanation:

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<u>a) Which barium salt will precipite first?</u>

In order to know this, we need to take a look at the Ksp of both salts. The given Ksp are:

Ksp 1: 2.1x10^-10 (BaCrO4)

Ksp 2: 1.3x10^-6 (BaC2O4)

Now, we can see that Ksp1 < Ksp 2, but what's this Ksp value means? a Ksp value means that an aqueous solution will form a precipite (So the solid formed, it's not soluble in water), As Ksp 1 is a smaller value than Ksp2, means that the concentrations of Ba and CrO4 are too small, and therefore, it takes more time to precipite. <em>Therefore, the BaC2O4 will precipite first.</em>

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In this, we know that the reaction taking place is the following:

BaCrO4(s) <--------> Ba^2+ + CrO4^2-   Ksp = 2.1x10^-10

The expression for Ksp is:

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So, we do the same thing we did in part b) but solving for C2O4:

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In this case, we calculate concentration of CrO4 and C2O4 with the value of Ba and it's respective Ksp, and then, calculate the ratio:

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[C2O4^2-] / [CrO4^2-] = 2.6x10^-4 / 4.2x10^-8

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