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Serggg [28]
3 years ago
5

How many atoms are in 2.5 moles of beryllium atoms?

Chemistry
1 answer:
Irina-Kira [14]3 years ago
8 0
As we know that there are avogadro no. of atoms in 9 g of beryllium.
1 mole of beryllium = 6.02 * 10^23 atoms
so 2.5 mole= 6.02*10^23*2.5 i.e = <span>15.055 × 10^23 atoms </span>
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Can someone help me?
Oduvanchick [21]

Answer:

<u>an element with a large number of valence electrons and a large atomic radius</u>

Explanation:

Electronegativity means a tedency when an atom attracts bonding electrons in a covalent bond situation.

» If an atom has many valency electrons [ <em>empty</em><em> </em><em>orbitals</em><em> </em><em>i</em><em>n</em><em> </em><em>o</em><em>u</em><em>t</em><em>e</em><em>r</em><em>m</em><em>o</em><em>s</em><em>t</em><em> </em><em>s</em><em>h</em><em>e</em><em>l</em><em>l</em><em> </em>], it has difficulty in attracting electrons hence electronegativity low.

» If an atom is large, its nuclear attraction force of incoming electrons is low hence low electronegativity.

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7 0
3 years ago
Non metals whose 2 forms<br> 1]very hard <br> 2] conductor of electricity
Usimov [2.4K]

Answer:

Diamond

Explanation:

Diamond has covalent bonds, which makes it a non-metal.

However, it also has a tetrahedral structure, which holds its C atoms together by strong forces, thus making it hard.

Diamond also has free-moving electrons due to its tetrahedral structure, thus making it possible to conduct electricity.

3 0
2 years ago
How many grams of solute are present in 1250 mL of a 1.34 M NaNO3 solution?
inysia [295]
He answer is 42 because you carry the one
5 0
4 years ago
How long does it take for dental stitches to dissolve.
kotykmax [81]
2-7 days, but depends on the procedure
8 0
2 years ago
A student takes a measured volume of 3.00 M HCl to prepare a 50.0 mL sample of 1.80 M HCI. What volume of 3.00 M HCI
frozen [14]

Answer:

30 mL VOLUME OF 3.0 M HCl SHOULD BE USED BY THE STUDENT TO MAKE A 1.80 M IN 50 mL OF HCl.

Explanation:

M1 = 3.00 M

M2 = 1.80 M

V2 = 50 .0 mL = 50 /1000 L = 0.05 L

V1 = unknown

In solving this question, we know that number of moles of a solution is equal to the molar concentration multiplied by the volume. To compare two samples, we equate both number of moles and substitute for the required component.

So we use the equation:

                                  M1 V1 = M2 V2

V1 = M2 V2 / M1

V2 = 1.80 * 0.05 / 3.0

V2 = 0.09 /3.0

V2 = 0.03 L or 30 mL

To prepare the sample of 1.80 M HCl in 50.0 mL from a 3.0 M HCl, 30 mL volume should be used.

5 0
3 years ago
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