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Crank
3 years ago
7

What is the mass of 1.2 mol IrI3?​

Chemistry
1 answer:
mr_godi [17]3 years ago
5 0

Answer:

690 g IrI₃

Explanation:

To convert from moles to grams, you have to use the molar mass of the compound. The molar mass of IrI₃ is 572.92 g/mol. You use this as the unit converter in this equation:

1.2molIrI3 * \frac{572.92g}{1mol} = 687.504 g IrI3

Round to the lowest number of significant figures which is 2 to get 690 g IrI₃.

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<u>Concepts used:</u>

1 mole of an element or a compound has 6.022 * 10²³ formula units

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<u>003 - </u><u>Number of CaH₂ formula units in 6.065 grams</u>

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<u>004 </u><u>- Mass of 6.34 * 10²⁴ formula units of NaBF₄</u>

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<em>Number of formula units = number of moles * 6.022*10²³</em>

Solving it for number of moles, we get:

Number of moles = Number of Formula units / 6.022* 10²³

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<u>005</u><u> - Number of moles in 9.78 * 10²¹ formula units of CeI₃</u>

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Number of moles = Number of Formula units / 6.022* 10²³

replacing the variables

Number of Moles = 9.78 * 10²¹ / 6.022*10²³

Number of Moles = 1.6 / 10²

Number of Moles = 1.6 * 10⁻² moles   OR   0.016 moles

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