All categories

3 years ago

What is the mass of 1.2 mol IrI3?

Chemistry

1 answer:

mr_godi [17]3 years ago

5 0

Answer:

690 g IrI₃

Explanation:

To convert from moles to grams, you have to use the molar mass of the compound. The molar mass of IrI₃ is 572.92 g/mol. You use this as the unit converter in this equation:

$1.2molIrI3 * \frac{572.92g}{1mol} = 687.504 g IrI3$

Round to the lowest number of significant figures which is 2 to get 690 g IrI₃.

You might be interested in

Which methods will help you properly identify pH with indicator paper? Check all that apply. Set a piece of pH paper in front of

monitta

Set a piece of pH paper in front of each solution before testing to keep organized.

Use a transfer pipet to remove a few drops from the solution to drop onto the paper.

Wait a minute or so before reading color.

Is the correct answer...

4 0

3 years ago

Read 2 more answers

What is missing from this graph? A. axis labels B. a trendline C. a title

Iteru [2.4K]

Answer:

Axis Labels

Explanation:

The axis labels are usually located on the x and y axis. This graph however is missing those.

hope this helps!

7 0

3 years ago

To the nearest 0.5 mL, what is the water volume in the graduated cylinder? mL?

AnnZ [28]

Answer:

14cm^3

Explanation:

6 0

2 years ago

Given the following thermodynamic data, calculate the lattice energy of LiCl:

tiny-mole [99]

Answer:

$\boxed{\text{-862 kJ/mol}}$

Explanation:

One way to calculate the lattice energy is to use Hess's Law.

The lattice energy U is the energy released when the gaseous ions combine to form a solid ionic crystal:

Li⁺(g) + Cl⁻(g) ⟶ LiCl(s); U = ?

We must generate this reaction rom the equations given.

(1) Li(s) + ½Cl₂ (g) ⟶ LiCl(s); ΔHf° = -409 kJ·mol⁻¹

(2) Li(s) ⟶ Li(g); ΔHsub = 161 kJ·mol⁻¹

(3) Cl₂(g) ⟶ 2Cl(g) BE = 243 kJ·mol⁻¹

(4) Li(g) ⟶Li⁺(g) +e⁻ IE₁ = 520 kJ·mol⁻¹

(5) Cl(g) + e⁻ ⟶ Cl⁻(g) EA₁ = -349 kJ·mol⁻¹

Now, we put these equations together to get the lattice energy.

E/kJ

(5) Li⁺(g) +e⁻ ⟶ Li(g) 520

(6) Li(g) ⟶ Li(s) -161

(7) Li(s) + ½Cl₂(g) ⟶ LiCl(s) -409

(8) Cl(g) ⟶ ½Cl₂(g) -121.5

(9) Cl⁻(g) ⟶ Cl(g) + e⁻ +349

Li⁺(g) + Cl⁻(g) ⟶ LiCl(s) -862

The lattice energy of LiCl is $\boxed{\textbf{-862 kJ/mol}}$ .

3 0

2 years ago

Help please I really really need it now

postnew [5]

1. A 2. B 5. B this is all I know hope it helps

5 0

2 years ago

What is the mass of 1.2 mol IrI3?​

What is the mass of 1.2 mol IrI3?