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3 years ago

As an object increases its speed, its kinetic energy

Physics

1 answer:

Juliette [100K]3 years ago

6 0

Answer:

Increase

Explanation:

Kinetic energy is the energy of motion--so the overall energy of that object would increase. Kinetic energy of an object is directly proportional to the square of its speed.

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Who invented the first practical incandescent light bulb?.

OverLord2011 [107]

Answer:

Edison

Explanation:

Among other notable inventions, Edison and his assistants developed the first practical incandescent lightbulb in 1879 and a forerunner of the movie camera and projector in the late 1880s.

6 0

3 years ago

Which of these would best define sound intensity? A) how fast the wave is traveling B) the frequency of the sound wave the power

faust18 [17]

Which of these would best define sound intensity?

A) how fast the wave is travelling

<u>B) the frequency of the sound wave the power of the sound wave per unit area the mass of the wave divided by its volume</u>

5 0

4 years ago

Read 2 more answers

Which of the following. Chemical represent the law of conservation of Matter?

vazorg [7]

Answer:

The answer is first one 1...

6 0

3 years ago

Bird bones have air pockets in them to reduce their weight—this also gives them an average density significantly less thanthat o

snow_tiger [21]

Answer:

41.4 g

41.4 cm³

1.08695 g/cm³

Explanation:

$\rho$ = Density of water = 1 g/cm³

Mass of water displaced will be the difference of the

$m=45-3.6\\\Rightarrow m=41.4\ g$

Mass of water displaced is 41.4 g

Density is given by

$\rho=\dfrac{m}{v}\\\Rightarrow v=\dfrac{m}{\rho}\\\Rightarrow v=\dfrac{41.4}{1}\\\Rightarrow v=41.4\ cm^3$

So, volume of bone is 41.4 cm³

Average density of the bird is given by

$\rho=\dfrac{45}{41.4}\\\Rightarrow \rho=1.08695\ g/cm^3$

The average density is 1.08695 g/cm³

3 0

4 years ago

Physical therapists know as you soak tired muscles in a hot tub, the water will cool down as you heat up. If a 67.9 kg person at

Lubov Fominskaja [6]

Answer:

c = 5032.8J/kg°C

Explanation:

the transfer of heat is given by

$Q_1=-Q_2\\\\Q=cm(T_f-T_i)$

c is the specific heat, m the mass and T the temperatures at equilibrium an at the beginning.

By replacing we obtain

$c_1m_1(T_f-T_{1i})=-c_2m_2(T_f-T_{2i})\\\\c_2=-\frac{c_1m_1(T_f-T_{1i})}{m_2(T_f-T_{2i})}=-\frac{(67.9kg)(4186J/kg\°C)(38.7\°C-37.1\°C)}{(50.2kg)(38.7\°C-40.5\°C)}\\\\c_2=5032.8\frac{J}{kg\°C}$

hope this helps!!

4 0

3 years ago