Hello,

Just for the fun, it's been a long time for that.

$f(30,5)=50\\

f(t+3,x)=f(t,x)-5\ ==\textgreater \dfrac{f(t+3,x)-f(t,x)}{3}= -\frac{5}{3} \\

f(t,x+2)=f(t,x)-3\ ==\textgreater\dfrac{f(t,x+2)-f(t,x)}{2}= -\frac{3}{2} \\

f(t+\Delta t,\Delta x)=f(f,t)+ \dfrac{\partial{f(t,x)}}{\partial{t}} *\Delta t+ \dfrac{\partial{f(t,x)}}{\partial{x}} *\Delta x\\

f(33,4)\approx f(30,5)- \dfrac{5}{3} *3-\dfrac{3}{2}*(-1)= 50- 5+1.5=46.5\\


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6 0

3 years ago

Find YZ please and thank you.

weqwewe [10]

Answer:

it should be YZ = 35

Step-by-step explanation:

7 0

3 years ago

Consider the following functions. f1(x) = 0, f2(x) = x, f3(x) = ex g(x) = c1f1(x) + c2f2(x) + c3f3(x) Solve for c1, c2, and c3 s

Len [333]

There are infinitely many solutions for any choice of $c_1$ and $c_2=c_3=0$ .