Answer:
103239.89 days
Explanation:
Kepler's third law states that the square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.
a³ / T² = 7.496 × 10⁻⁶ (a.u.³/days²)
where,
a is the distance of the semi-major axis in a.u
T is the orbit time in days
Converting the mean distance of the new planet to astronomical unit (a.u.)
1 a.u = 9.296 × 10⁷ miles
Substituting the values into Kepler's third law equation;
(days)²
T = 103239.89 days
An estimate time T for the new planet to travel around the sun in an orbit is 103239.89 days
Answer: 1018.26 m/s
Explanation:
Approaching the orbit of the Moon around the Earth to a circular orbit (or circular path), we can use the equation of the speed of an object with uniform circular motion:
Where:
is the speed of travel of the Moon around the Earth
is the Gravitational Constant
is the mass of the Earth
is the distance from the center of the Earth to the center of the Moon
Solving:
This is the speed of travel of the Moon around the Earth
Answer:
An Energy held by an object because of its position relative by other objects
Explanation:
Using Ohm's Law, we can derived from this the value of resistance. If I=V/R, therefore, R = V/I
Substituting the values to the given,
P = Power = ?
R = Resistance = ?
V = Voltage = 2.5 V
I = Current = 750 mA
R = V/I = 2.5/ (750 x 10^-3)
R = 3.33 ohms
Calculating the power, we have P = IV
P = (750 x 10^-3)(2.5)
P = 1.875 W
The power consumption is the power consumed multiply by the number of hours. In here, we have;
1.875W x 4 hours = 7.5 watt-hours
28 because that’s the part of the problem in adopt me
