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Wittaler [7]
2 years ago
8

Consider the diatomic molecule oxygen O2 which is rotating in the xy plane about the z axis passing through its center, perpendi

cular to its length. The mass of each oxygen atom is 2.66 × 10−26 kg, and at room temperature, the average separation distance between the two oxygen atoms is 2.2 × 10−10 m (treat the atoms as point masses). If the angular speed of the molecule about the z axis is 5.49 × 1012 rad/s, what is its rotational kinetic energy? Answer in units of J.
Physics
1 answer:
Brilliant_brown [7]2 years ago
3 0

Answer: 9.7*10^-21 J

Explanation:

Given

Mass of oxygen atom, m = 2.66*10^-26 kg

Separation distance between the two atoms, r = 2.2*10^-10 m

Angular speed, w = 5.49*10^12 rad/s

First, we start by finding our moment of Inertia, I, using the relation

I = 1/2mr²

I = 1/2 * 2.66*10^-26 * (2.2*10^-10)²

I = 1/2 * 1.2874*10^-45

I = 6.437*10^-46 kgm²

The Rotational Kinetic Energy is given by

KE = 1/2Iw²

Now, using this value of I, we plug it in the energy equation.

KE = 1/2 * 6.437*10^-46 * (5.49*10^12)²

KE = 1/2 * 1.94*10^-20

KE = 9.7*10^-21 J

Thus, the rotational kinetic energy is 9.7*10^-21 J

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<h3>What is simple harmonic motion?</h3>

Simple harmonic motion, in physics, repetitive movement back and forth through an equilibrium, or central, position, so that the maximum displacement on one side of this position is equal to the maximum displacement on the other side.

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From the calculations above, the maximum kinetic energy, maximum potential energy and the maximum mechanical energy are equal to 7.56J.

Learn more on simple harmonic motion here;

brainly.com/question/15556430

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