Answer: 9.7*10^-21 J
Explanation:
Given
Mass of oxygen atom, m = 2.66*10^-26 kg
Separation distance between the two atoms, r = 2.2*10^-10 m
Angular speed, w = 5.49*10^12 rad/s
First, we start by finding our moment of Inertia, I, using the relation
I = 1/2mr²
I = 1/2 * 2.66*10^-26 * (2.2*10^-10)²
I = 1/2 * 1.2874*10^-45
I = 6.437*10^-46 kgm²
The Rotational Kinetic Energy is given by
KE = 1/2Iw²
Now, using this value of I, we plug it in the energy equation.
KE = 1/2 * 6.437*10^-46 * (5.49*10^12)²
KE = 1/2 * 1.94*10^-20
KE = 9.7*10^-21 J
Thus, the rotational kinetic energy is 9.7*10^-21 J