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3 years ago

What would happen if the gravitational force between the moon suddenly disappeared?

1 answer:

8 0

So many thinks the water wouldnt have as many waves it could result in no season and even an ice age. Nights would be darker. In result in the tides changing animals will be confused, some species rely on the tides for food and shelter. So without that it would cause a chain of mass extinction.

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If I put one hand in hot tap water and the other in cold tap water then both in the same warm tap water what will happen

Natalija [7]

Answer:

you will feel warm

Explanation:

beacause your body will get the warm from warm water tap..

7 0

3 years ago

The mass of the Earth is 5.98 × 1024 kg . A 11 kg bowling ball initially at rest is dropped from a height of 2.63 m. The acceler

jekas [21]

Answer:

v = 7.18_m/s

Explanation:

Velocity of the earth towards the ball is = velocity of the ball moving towards earth

For object in free fall, we have

Where

v = final velocity

u = initial velocity

g = acceleration due to gravity

t = time

S = height of ball above ground

v^2 = u^2 - 2×g×(-S)

= 0 + 2×9.8×2.63 = 51.55_m^2/s^2

Velocity of the ball just before it hits the ground is

v = 7.18_m/s

3 0

3 years ago

Explain how the wave behave as the Frequency changes using the characteristic described in

Serggg [28]

Let's find the relationship

$\\ \rm\Rrightarrow E=h\nu$

$\\ \rm\Rrightarrow \lambda=\dfrac{c}{\nu}$

So if frequency increases Energy of the wave increases and wavelength decreases and vice-versa

3 0

2 years ago

The Hubble Space Telescope orbits the Earth at approximately 612,000m altitude. Its mass is 11,100 kg and the mass of earth is 5

nexus9112 [7]

Answer:

7.55 km/s

Explanation:

The force of gravity between the Earth and the Hubble Telescope corresponds to the centripetal force that keeps the telescope in uniform circular motion around the Earth:

$G\frac{mM}{R^2}=m\frac{v^2}{R}$

where

$G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2}$ is the gravitational constant

$m=11,100 kg$ is the mass of the telescope

$M=5.97\cdot 10^{24} kg$ is the mass of the Earth

$R=r+h=6.38\cdot 10^6 m+612,000 m=6.99\cdot 10^6 m$ is the distance between the telescope and the Earth's centre (given by the sum of the Earth's radius, r, and the telescope altitude, h)

v = ? is the orbital velocity of the Hubble telescope

Re-arranging the equation and substituting numbers, we find the orbital velocity:

$v=\sqrt{\frac{GM}{R}}=\sqrt{\frac{(6.67\cdot 10^{-11})(5.97\cdot 10^{24} kg)}{6.99\cdot 10^6 m}}=7548 m/s=7.55 km/s$

6 0

3 years ago

If the action force is the swimmer pushing water in the leftward direction, what is the reaction force?

Sphinxa [80]

According to Newton's Third Law of Motion, to every action, there is an equal and opposite reaction; action and reaction act on different bodies.
Here, the action force is in the leftward direction, so the reaction will be in the opposite direction.
If the action force is the swimmer pushing water in the leftward direction, then the reaction force is in the rightward direction.
And the reaction force will be given by the water on the swimmer.

Answer:

The reaction force is the water pushing the swimmer in the rightward direction.

Hope you could get an idea from here.

Doubt clarification - use comment section.

3 0

2 years ago