Answer:
V = 134.5 L
Explanation:
Given data:
Number of moles of KClO₃ = 4 mol
Litters of oxygen produced at STP = ?
Solution:
Chemical equation:
2KClO₃ → 2KCl + 3O₂
Now we will compare the moles of KClO₃ with oxygen.
KClO₃ : O₂
2 : 3
4 ; 3/2×4 = 6 mol
Litters of oxygen at STP:
PV = nRT
V = nRT/P
V = 6 mol × 0.0821 atm.L/mol.K × 273 K / 1atm
V = 134.5 L / 1
V = 134.5 L
Answer:
<em>Friction between the hand and the wood decreased.</em>
Explanation:
The texture of the wood went from rough → smooth! This means friction between the hand and the wood was notably decreased.
According to this prompt, the carpenter used <em>sandpaper </em>against the wood. Sandpaper just so happens to be a very abrasive substance. The sandpaper polished and leveled out the wood which wore all the jutting bits away.- overall, making it much smoother and more pleasant to touch!
<em>Hope I was of assistance! </em><u><em>Have a nice day and Spread the Love! <3</em></u>
Ever seen a waterfall ? what do you think happens when all that water slams into the ground below ? same as when you turn a hosepipe on a flowerbed.
also, there's hydraulic cracking where water gets into cracks and freezes, splitting rocks apart.
fast moving water can carry sediment and roll rocks along the bottom. if the water slows down, it drops the rocks and heavier sediment. if it floods a field, say, then drains away, the grass will also filter smaller particles out, or the water might evaporate and leave fine sediment behind.
<h3>
Answer:</h3>
3.342 x 10^24 molecules of water
<h3>
Explanation:</h3>
Given;
Mass of water = 100.0 g
Required to determine the number of molecules in 100.0 g of water
Using Avogadro's constant
1 mole of a compound contains 6.022 × 10^22 molecules
Thus;
1 mole of H₂O contains 6.022 × 10^23 molecules
But;
1 mole = 18.02 g/mol
Therefore;
18.02 g of water contains 6.022 × 10^23 molecules
100.0 g of water will have;
= (100. 0 g ×6.022 × 10^23 molecules) ÷ 18.02
= 3.342 x 10^24 molecules
Answer:
it dissolve faster in higher temperature hope it's right
