a)
The volume of the sports hall can be calculated using the equation
where
a, b, c are the measures of the sizes of the hall
For the sport hall in this problem, we have
a = 80 m
b = 40 m
c = 15 m
Substituting into the equation, we find
b)
Being a gas, the air fills the whole sport halls, therefore its volume is equal to the volume of the sports hall.
The relationship between the mass, the volume and the density of the air is
where
is the density
m is the mass
V is the volume
Here we have:
Solving for m, we find the mass of air:
Answer:
moving a magnet into a coil of wire in a closed circuit.
Ed 2020
In my opinion, it would be coke because of all the pressure
To solve the problem, apply the concepts related to constructive and destructive interference. For this purpose, we will start by defining the distance from the dark fringe from the central maximum in terms of the slit separation, the number of fringe the wavelength and the distance of the screen to the slit. Mathematically this is,
Here,
d = Slit separation
n = Number of fringe
= Distance of the dark fringe from the central maximum
D = Distance of the screen to the slit
= Wavelength
Our values are given as,
Replacing,
Therefore the screen is located from the slit to 9.61m