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Ulleksa [173]
3 years ago
9

1.4 The inside of a sports hall measures 80 m

Physics
1 answer:
NISA [10]3 years ago
6 0

a) 48000 m^3

The volume of the sports hall can be calculated using the equation

V=a\cdot b \cdot c

where

a, b, c are the measures of the sizes of the hall

For the sport hall in this problem, we have

a = 80 m

b = 40 m

c = 15 m

Substituting into the equation, we find

V=(80)(40)(15)=48,000 m^3

b) 62400 kg

Being a gas, the air fills the whole sport halls, therefore its volume is equal to the volume of the sports hall.

The relationship between the mass, the volume and the density of the air is

\rho = \frac{m}{V}

where

\rho is the density

m is the mass

V is the volume

Here we have:

\rho = 1.3 kg/m^3

V=48000 m^3

Solving for m, we find the mass of air:

m=\rho V = (1.3)(48000)=62,400 kg

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An electron in a vacuum is first accelerated by a voltage of 51400 V and then enters a region in which there is a uniform magnet
zimovet [89]

Answer:

       F = 8.6 10⁻¹² N

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Final. Electron with velocity, just out of the electric field

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Now we can use the equation of the magnetic force

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       For this exercise we use the law of conservation of energy

Initial. Field energy with the electron at rest

         Emo = U = q DV

Final. Electron with velocity, just out of the electric field

         Emf = K = ½ m v2

          Emo = Emf

          .e DV = ½ m v2

          .v = RA 2 e DV / m

          .v = RA (2 1.6 10-19 51400 / 9.1 10-31)

           .v = RA (1.8075 10 16)

           .v = 1,344 108 m / s

Now we can use the equation of the magnetic force

         F = q v x B

Since the speed and the magnetic field are perpendicular the force that

        F = e v B

       F = 1.6 10-19 1,344 108 0.4

       F = 8.6 10-12 N

5 0
2 years ago
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Answer:

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