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Ulleksa [173]
3 years ago
9

1.4 The inside of a sports hall measures 80 m

Physics
1 answer:
NISA [10]3 years ago
6 0

a) 48000 m^3

The volume of the sports hall can be calculated using the equation

V=a\cdot b \cdot c

where

a, b, c are the measures of the sizes of the hall

For the sport hall in this problem, we have

a = 80 m

b = 40 m

c = 15 m

Substituting into the equation, we find

V=(80)(40)(15)=48,000 m^3

b) 62400 kg

Being a gas, the air fills the whole sport halls, therefore its volume is equal to the volume of the sports hall.

The relationship between the mass, the volume and the density of the air is

\rho = \frac{m}{V}

where

\rho is the density

m is the mass

V is the volume

Here we have:

\rho = 1.3 kg/m^3

V=48000 m^3

Solving for m, we find the mass of air:

m=\rho V = (1.3)(48000)=62,400 kg

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Answer:

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Part B

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Part C

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Explanation:

Part A

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The given parameters are;

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The efficiency of the engine = (The energy output)/(The energy input)= 1,000J/10,00J = 0.1

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Part B

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The change in internal energy, ΔU is given as follows;

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P = The constant pressure applied

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