It takes 100,832 J of work to lift an elevator 18.3 meters. If this is done in 21.0 seconds, what is the average power of the el
evator during the process? Explain your answer.
1 answer:
Answer:
4.80 kW
Explanation:
Power = work / time
P = 100,832 J / 21.0 s
P ≈ 4800 W
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