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3 years ago

11

It takes 100,832 J of work to lift an elevator 18.3 meters. If this is done in 21.0 seconds, what is the average power of the el

evator during the process? Explain your answer.

1 answer:

34kurt3 years ago

6 0

Answer:

4.80 kW

Explanation:

Power = work / time

P = 100,832 J / 21.0 s

P ≈ 4800 W

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Answer:

There are different ways to investigate density. In this required practical activity, it is important to:

record the mass accurately

measure and observe the mass and the volume of the different objects

use appropriate apparatus and methods to measure volume and mass and use that to investigate density

Explanation:

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3 years ago

A lawn roller is rolled across a lawn by a force of 107 N along the direction of the handle, which is 13.5 ◦ above the horizonta

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Answer:

22.02 m

Explanation:

given,

Force, F = 107 N

angle made with horizontal = 13.5◦

Power develop by the lawn roller = 69.4 W

time = 33 s

distance = ?

Force along horizontal= F cos θ

= 107 cos 13.5°= 104 N

Power = $\dfrac{work\ done}{time}$

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Work done= Force x displacement

displacement= $\dfrac{2290.2}{104}$

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3 years ago

You normally drive on the freeway between San Diego and Los Angeles at an average speed of 105 km/h (65 mi/h), and the trip take

valkas [14]

Answer: 2 hr 45 min

Explanation:

Given

The average speed between San Diego and Los Angeles is $105\ kmph$

time taken for this trip is $1\ hr\ 50\ min\ or\ \frac{11}{6}\ hr$

Distance between San Diego and Los Angeles is

$\Rightarrow d=105\times \dfrac{11}{6}\\\\\Rightarrow d=192.5\ km$

For Friday afternoon, the average speed is $70\ km/h$

time taken to complete the trip is

$\Rightarrow t=\dfrac{192.5}{70}\\\\\Rightarrow t=2.75\ hr\ or\ 2\ hr\ 45\ min$

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3 years ago

Consider an electrical transformer that has 10 loops on its primary coil and 20 loops on its secondary coil. What is the current

rusak2 [61]

Answer:

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Explanation:

Transformer: A transformer is an electromechanical device that is used to change the voltage of an alternating current.

The current and the number of loops in a transformer is related as shown below

Ns/Np = Ip/Is........................... Equation 1

Where Ns = Secondary loop, Np = primary loop, Ip = primary current, Is = secondary current.

Making Is the subject of the equation

Is = NpIp/Ns........................ Equation 2

Given: Np = 10 loops, Ns = 20 loops, Ip = 5.0 A.

Substitute into equation 2

Is = (10×5.0)/20

Is = 50/20

Is = 2.5 A.

Hence the current in the primary coil = 2.5 A.

The right option is C. 2.5 A

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3 years ago

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Eddi Din [679]

Answer:

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3 years ago