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-BARSIC- [3]
3 years ago
11

It takes 100,832 J of work to lift an elevator 18.3 meters. If this is done in 21.0 seconds, what is the average power of the el

evator during the process? Explain your answer.
Physics
1 answer:
34kurt3 years ago
6 0

Answer:

4.80 kW

Explanation:

Power = work / time

P = 100,832 J / 21.0 s

P ≈ 4800 W

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Answer:

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Explanation:

The function s(t) represents the position of an object at time t moving along a line such that,

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and

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3 years ago
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