Take breaks and drink plenty of water not to much because it will make you sick sorry apparently pu ke is a bad word.
Given conditions:
height of object = 7.5cmdistance of object from mirror = 14 cmfocus length = -7 cmimage distance = ?
Using mirror formula:
1/(focus length) = 1/(object distance) + 1/(image distance)
or, -1/7 = 1/14 + 1/(image distance)
or, image distance = -4.66cm (the image formed is a virtual image)
Also, magnification of image is:
image height /height of object = - image distance /object distance
or, image height = - image distance / object distance * height of object
or, image height = -(-4.66) / 14 * 7.5 = 2.49 = 3(nearest whole number)
Answer:
2.85 s .
Explanation:
y(t) = y(0) + v₀t + 1/2 gt²
y(t) is vertical displacement , y(0) is initial position , v₀ is initial velocity and t is time required to make vertical displacement and g is acceleration due to gravity.
Here y(0) is zero , v₀ = 14 m/s , g = 9.8 m s⁻² , y(t ) = 0 , as the pumpkin after time t comes back to its initial position, that is ground .
We shall take v₀ as negative as it is in upward direction and g as positive as it acts in downward direction
Put the values in the equation above,
0 = 0 - 14t + 1/2 x 9.8 t²
14 t = 1/2 x 9.8 t²
t = 28 / 9.8
t = 2.85 s .
1 volt = 1 joule per coulomb
It takes 1 joule of work to force a coulomb of charge enough closer to a charge
with the same sign to raise its potential 1 volt.
If you allow 1 coulomb of charge to fall to where its potential is 1 volt less,
it gives up 1 joule of energy.
Answer: 0.013 seconds
Explanation:
Given that
Mass of golf ball = 0.058 kg
Force = 272 N
Velocity = 62.0 m/s
Time taken = ?
Recall that force is the rate of change of momentum per unit time
i.e Force = Change in momentum / Time
i.e Force = (Mass x velocity) / Time
272N = (0.058 kg x 62.0 m/s) / Time
272N = 3.6kgm/s / Time
Time = (3.6kgm/s / 272N)
Time = 0.013 seconds
Thus, the ball was in contact with the club for 0.013 seconds
