Answer:
Explanation:
Volume of lead object = volume of aluminium object = V
mass of lead object > mass of aluminium object
When both the objects immersed in water, the buoyant force acting on both the objects.
Buoyant force = Volume immersed x density of water x gravity
As the volume of both the objects is same, so the buoyant force acting on both the objects is same.
So, weight in air of lead object is more than the weight in air of aluminium object.
the answer wil be 2.36+3.38+0.355+1.06=7.155
The power dissipated is simply V^2/R
where V = 120 volts RMS
and R = 60 Ω
Answer:
The answer is 5
Explanation:
The maximum interference is:
m * λ = d * sinθi
Where m = 0,1,2,3,...
The first minimum diffraction is:
λ = a * sinθd
|sinθi| < sinθd
Where
(|m| * λ)/d < λ/a
|m| < d/a = 2.5
|m|max = 2
It can be concluded that coherent monochromatic light passes through the slits, therefore the maximum number of interference is 5.
