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Kay [80]
2 years ago
7

A rocket is launched from the ground and travels in a straight path. The angle of inclination of the rocket's path is 1.2 radian

s. (That is, the rocket's path and the ground form an angle with a measure of 1.2 radians.)]
Required:
a. What is the slope of the rocket's path?
b. If the rocket has traveled 85 yards horizontally since it was launched, how high is the rocket above the ground? _____yards.
c. At some point in time, the rocket is 313 yards above the ground. How far has the rocket horizontally (since it was launched) at this point in time? _____yards
Mathematics
1 answer:
gladu [14]2 years ago
3 0

Answer:

a)S=2.57

b)H=203.2yard

c)X=121.79yards

Step-by-step explanation:

From the question we are told that:

Angle \theta=1.2=68.755^o

a)

Generally the equation for Slope is mathematically given by

 S=tan \theta

 S=tan 68.755

 S=2.57

b)

Given the right Angle triangle with horizontal distance x=85yard

Generally the equation for Height traveled is mathematically given by

 H=tan\theta*x

 H=2.57*85

 H=218.45

 H=203.2yard

c)

Generally the equation for Horizontal Distance traveled at 313 height traveled is mathematically given by

X=\frac{313}{tan65.75}

X=\frac{313}{2.57}

X=121.79yards

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