The mass of nitric acid required to make the given solution is 0.0627 g.
The given parameters:
- <em>Volume of the acid, V = 250 mL</em>
- <em>pH of the acid, = 2.4</em>
The hydrogen ion (H⁺) concentration of the nitric acid is calculated as follows;
The molarity of the nitric acid is calculated as follows;
The number of moles of the nitric acid is calculated as follows;
The molar mass of nitric acid is calculated as;
The mass of the nitric acid contained in the calculated number of moles is calculated as;
Thus, the mass of nitric acid required to make the given solution is 0.0627 g.
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Answer:
22.6881 Grams of CO
Explanation:
Fe2O3 + 3CO = 3CO2 + 2Fe
Ratio
1:3 = 3:2
How many grams of CO are needed to produce 30.2 grams of Fe
Fe2O3 Molar mass: 159.69 g/mol
CO Molar mass: 28.01 g/mol
Fe Atomic mass: 55.845
Ok so our end result is 30.2 Grams of Fe, we have 2 Fe so we have 15.1 Grams per Fe
15.1/55.845 = 0.27
So then we multiply this by 3 as we we know the ratio and get get 0.81 required as this is 3CO.
So we need 0.81 Moles of CO so we need 22.6881 Grams of CO.
Answer:
i think is probably A
Explanation:
because at constant temperature, the product of the pressure and volume of a given mass of and ideal gass in a closed system is always constant
Answer:
fluorine is the most electronegative element,
Explanation:
while francium is one of the least electronegative. (Helium, neon, and argon are not listed in the Pauling electronegativity scale, although in the Allred-Rochow scale, helium has the highest electronegativity.)
