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Brilliant_brown [7]
3 years ago
15

en la parte inferior de un tanque de 7 m de altura se coloca un tubo de 38 mm de diámetro ¿con que velocidad fluirá el agua por

él, si el tanque está lleno? si el tubo de 38 mm de diámetro se conecta a otro de 13 mm ¿cuál será la velocidad del agua al pasar por este segundo tubo?​
Physics
2 answers:
Luden [163]3 years ago
7 0
Txitxitxitdursy red tock kgxgjzitduuurdut
JulsSmile [24]3 years ago
6 0

Answer:

yo no se

Explanation:

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How much work is done when a porcelain vase with mass of 2.5 kg is lifted up 3 m to a shelf? (HINT- Weight can be used as Force
alexdok [17]
Work = force x distance
F= 2.5
D= 3
Work = 2.5 x 3 =7.5
Work = 7.5 J
J=Jules (Jules is the unit uses to calculate work)
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3 years ago
Acid rain contributes to soil erosion. Acid rain can be caused by 
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Resistivity of metallic wire
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nature of material

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3 years ago
A capacitor is charges with 9.6 nC and has a 120 V potential difference between its terminals. Compute
IRINA_888 [86]

Explanation:

Q = CV

where C = capacitance

V = potential difference

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4 0
3 years ago
A red laser from the physics lab is marked as producing 632.8-nm light. When light from this laser falls on two closely spaced s
BARSIC [14]

Answer:

The wavelength is  \lambda_R  =  649 *10^{-9}\ m

Explanation:

From the question we are told that

   The wavelength of the red laser is  \lambda_r  =  632.8 \ nm =  632.8 *10^{-9}\ m

    The spacing between  the fringe is  y_r  =  6.00\ mm =  6.00*10^{-3}  \  m

   The spacing between  the fringe for smaller laser point  is  y_R   = 6.19 \ mm =  6.19 *10^{-3} \  m

      Generally the spacing between  the fringe is mathematically represented as

       y  =  \frac{D *  \lambda  }{d}

Here  D is the distance to the screen

    and  d is the distance of the slit separation

Now for both laser red light light and  small laser  point  D and  d are same for this experiment

So

         \frac{y_r}{\lambda_r}  =  \frac{D}{d}

=>      \frac{y_r}{\lambda_r}  = \frac{y_R}{\lambda_R}

Where \lambda_R  is the wavelength produced by the small laser pointer

  So

           \frac{6.0 *10^{-3}}{ 632.8*10^{-9}}  = \frac{ 6.15 *10^{-9}}{\lambda_R}

=>       \lambda_R  =  649 *10^{-9}\ m

7 0
3 years ago
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