Answer:
Yes
Step-by-step explanation:
3 x - 2 y = 10
( - 2 , - 8 )
We know that coordinates are put in the form ( x , y ) and from that we can work out that x = -2 and y = -8
Now we just substitute x = -2 and y = -8 into 3 x - 2 y = 10
3 x - 2 y = 10
{ 3 × ( - 2 ) } - { 2 × ( - 8 ) } = 10
{ - 6 } - { - 16 } = 10
- 6 + 16 = 10 True
Answer:
/ Solve equation [2] for the variable y
[2] 7y = 12x + 17
[2] y = 12x/7 + 17/7
// Plug this in for variable y in equation [1]
[1] 9x - 2•(12x/7+17/7) = -3
[1] 39x/7 = 13/7
[1] 39x = 13
// Solve equation [1] for the variable x
[1] 39x = 13
[1] x = 1/3
// By now we know this much :
x = 1/3
y = 12x/7+17/7
// Use the x value to solve for y
y = (12/7)(1/3)+17/7 = 3
Solution :
{x,y} = {1/3,3}
Step-by-step explanation:
Answer:
16 meters
Step-by-step explanation:
The height function is given by:
![h(x)=-(x+1)(x-7)\\h(x)=-(x^2+x-7x-7)\\h(x)=-x^2+6x+7](https://tex.z-dn.net/?f=h%28x%29%3D-%28x%2B1%29%28x-7%29%5C%5Ch%28x%29%3D-%28x%5E2%2Bx-7x-7%29%5C%5Ch%28x%29%3D-x%5E2%2B6x%2B7)
The value of x, in seconds, for which the derivate of the height function is zero, is the time at which the maximum height occurs:
![\frac{dh(x)}{dx}= h'(x)=-2x+6=0\\x=3](https://tex.z-dn.net/?f=%5Cfrac%7Bdh%28x%29%7D%7Bdx%7D%3D%20h%27%28x%29%3D-2x%2B6%3D0%5C%5Cx%3D3)
For x = 3 seconds, the height is:
![h(3)=-(3^2)+6*3+7\\h(3)=16\ m](https://tex.z-dn.net/?f=h%283%29%3D-%283%5E2%29%2B6%2A3%2B7%5C%5Ch%283%29%3D16%5C%20m)
The maximum height that the ball will reach is 16 meters.
Answer:
Its a square. if you graph it, you would see.
Step-by-step explanation: