Answer:
A meteor hit earth they think the moon is created from debris from earth but really God created it UwU
Explanation:
Answer:
1) After adding 15.0 mL of the HCl solution, the mixture is before the equivalence point on the titration curve.
2) The pH of the solution after adding HCl is 12.6
Explanation:
10.0 mL of 0.25 M NaOH(aq) react with 15.0 mL of 0.10 M HCl(aq). Let's calculate the moles of each reactant.
![nNaOH=\frac{0.25mol}{L} .10.0 \times 10^{-3} L=2.5 \times 10^{-3}mol](https://tex.z-dn.net/?f=nNaOH%3D%5Cfrac%7B0.25mol%7D%7BL%7D%20.10.0%20%5Ctimes%2010%5E%7B-3%7D%20L%3D2.5%20%5Ctimes%2010%5E%7B-3%7Dmol)
![nHCl=\frac{0.10mol}{L} \times 15.0 \times 10^{-3} L=1.5 \times 10^{-3}mol](https://tex.z-dn.net/?f=nHCl%3D%5Cfrac%7B0.10mol%7D%7BL%7D%20%5Ctimes%2015.0%20%5Ctimes%2010%5E%7B-3%7D%20L%3D1.5%20%5Ctimes%2010%5E%7B-3%7Dmol)
There is an excess of NaOH so the mixture is before the equivalence point. When HCl completely reacts, we can calculate the moles in excess of NaOH.
NaOH + HCl ⇒ NaCl + H₂O
Initial 2.5 × 10⁻³ 1.5 × 10⁻³ 0 0
Reaction -1.5 × 10⁻³ -1.5 × 10⁻³ 1.5 × 10⁻³ 1.5 × 10⁻³
Final 1.0 × 10⁻³ 0 1.5 × 10⁻³ 1.5 × 10⁻³
The concentration of NaOH is:
![[NaOH]=\frac{1.0 \times 10^{-3} mol }{25.0 \times 10^{-3} L} =0.040M](https://tex.z-dn.net/?f=%5BNaOH%5D%3D%5Cfrac%7B1.0%20%5Ctimes%2010%5E%7B-3%7D%20mol%20%7D%7B25.0%20%5Ctimes%2010%5E%7B-3%7D%20L%7D%20%3D0.040M)
NaOH is a strong base so [OH⁻] = [NaOH].
Finally, we can calculate pOH and pH.
pOH = -log [OH⁻] = -log 0.040 = 1.4
pH = 14 - pOH = 14 - 1.4 = 12.6
Answer:
![\boxed{\text{2408 min}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Ctext%7B2408%20min%7D%7D)
Explanation:
The integrated rate law for radioactive decay is
![\ln\dfrac{N_{0}}{N_{t}} = kt](https://tex.z-dn.net/?f=%5Cln%5Cdfrac%7BN_%7B0%7D%7D%7BN_%7Bt%7D%7D%20%3D%20kt)
1. Calculate the decay constant
![\begin{array}{rcl}\ln \dfrac{100}{90} & = & k \times 366\\\\1.054 & = & 366k\\\\k & = & \dfrac{1.054 }{366}\\\\k & = & 2.879 \times 10^{-4} \text{ min}^{-1}\\\end{array}\\\\](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7D%5Cln%20%5Cdfrac%7B100%7D%7B90%7D%20%26%20%3D%20%26%20k%20%5Ctimes%20366%5C%5C%5C%5C1.054%20%26%20%3D%20%26%20366k%5C%5C%5C%5Ck%20%26%20%3D%20%26%20%5Cdfrac%7B1.054%20%7D%7B366%7D%5C%5C%5C%5Ck%20%26%20%3D%20%26%202.879%20%5Ctimes%2010%5E%7B-4%7D%20%5Ctext%7B%20min%7D%5E%7B-1%7D%5C%5C%5Cend%7Barray%7D%5C%5C%5C%5C)
2. Calculate the half-life
![t_{\frac{1}{2}} = \dfrac{\ln2}{k}\\\\t_{\frac{1}{2}} = \dfrac{\ln2}{2.879 \times 10^{-4} \text{ min}^{-1}} = \text{2408 min}\\\\\text{The half-life for decay is } \boxed{\textbf{2408 min}}](https://tex.z-dn.net/?f=t_%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%3D%20%5Cdfrac%7B%5Cln2%7D%7Bk%7D%5C%5C%5C%5Ct_%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%3D%20%5Cdfrac%7B%5Cln2%7D%7B2.879%20%5Ctimes%2010%5E%7B-4%7D%20%5Ctext%7B%20min%7D%5E%7B-1%7D%7D%20%3D%20%5Ctext%7B2408%20min%7D%5C%5C%5C%5C%5Ctext%7BThe%20half-life%20for%20decay%20is%20%7D%20%5Cboxed%7B%5Ctextbf%7B2408%20min%7D%7D)
Answer:
A)16.3% (Hexane's formula is C6H14)
I suppose it would be forest because in order to have organic matter the soil needs to be rich and fertile,therefore it is forest.