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Ymorist [56]
3 years ago
12

Sodium burns in chlorine to form sodium chloride, NaCl. How many grams of sodium chloride will be formed when 1.8 g of sodium is

burned in 2.00 g of chlorine? What is the excess reactant in this reaction? What is the limiting reactant? How much of the excess reactant remains unreacted?
Chemistry
1 answer:
likoan [24]3 years ago
7 0
I think its Na as excess and Cl as limiting reagent and amount left unreacted is 0.021 mol
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A gas occupies 2.0 m3 at 100.0k and exerts a pressure of 100.0kPa. What volume will the gas occupy if the temperature is increas
Svetradugi [14.3K]
According to ideal gas equation, we know for 1 mole of gas: PV=RT
where P = pressure,  T = temperature, R = gas constant, V= volume
If '1' and '2' indicates initial and final experimental conditions, we have
\frac{P1V1}{P2V2} =  \frac{T1}{T2}

Given that: V1 = 100.0 kPa, T1 = 100.0 K, V1 = 2.0 m3, T2 = 400 K, P2 = 200.0 kPa

∴ on rearranging above eq., we get V2 = \frac{P1V1T2}{T1} =  \frac{100 X 2 X 400}{200X100}
∴ V2 = 4 m3 
7 0
3 years ago
Potassium chlorate decomposes into potassium chloride and oxygen gas. How many grams of oxygen are produced when 1.06 grams of p
kifflom [539]

The amount of oxygen that are produced when 1.06 grams of potassium chlorate decompose completely is 0.64 grams.

<h3>What is the relation between mass & moles?</h3>

Relation between the mass and moles of any substance will be represented as:

  • n = W/M, where
  • W = given mass
  • M = molar mass

Moles of potassium chlorate = 1.66g / 122.5g/mol = 0.0135mole

Given chemical reaction is:

2KClO₃ → 2KCl + 3O₂

From the stoichiometry of the reaction, it is clear that:

2 moles of KClO₃ = produces 3 moles of O₂

0.0135 moles of KClO₃ = produces (3/2)(0.0135)=0.02 moles of O₂

Mass of oxygen = (0.02mol)(32g/mol) = 0.64 g

Hence produced mass of oxygen is 0.64 grams.

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5 0
2 years ago
The radios of a atom is defined as
telo118 [61]

Answer:

Atomic radius...........

6 0
3 years ago
What is the main difference between active and passive transport?
masha68 [24]

Answer:

active transport requires energy and passive transport does not require energy

Explanation:

8 0
2 years ago
PLEASE ANSWER QUICKLY !!! FOR MY CHEMISTRY CLASS !!!!!
Sergio039 [100]

The density of the unknown metal, given the data is 1.67 g/mL

<h3>What is density? </h3>

The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as

Density = mass / volume

With the above formula, we can determine the density of the unknown metal. Details below:

<h3>How to determine the density </h3>
  • Mass of unknown metal = 20 - 0 = 20 g
  • Volume of unknown metal = 12 - 0 = 12 mL
  • Density of unknown metal =?

Density = mass / volume

Density of unknown metal = 20 / 12

Density of unknown metal = 1.67 g/mL

Thus, the density of unknown metal is 1.67 g/mL

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4 0
1 year ago
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