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Ymorist [56]
3 years ago
12

Sodium burns in chlorine to form sodium chloride, NaCl. How many grams of sodium chloride will be formed when 1.8 g of sodium is

burned in 2.00 g of chlorine? What is the excess reactant in this reaction? What is the limiting reactant? How much of the excess reactant remains unreacted?
Chemistry
1 answer:
likoan [24]3 years ago
7 0
I think its Na as excess and Cl as limiting reagent and amount left unreacted is 0.021 mol
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An IV bag is labeled as 0.800% w/w sodium chloride in water solution with a density of 1.036g/mL. What is the concentration of s
Goryan [66]

Answer:

[NaCl] = 0.14 M

[NaCl] = 0.14 m

Mole fraction of NaCl → 2.48×10⁻³

Explanation:

This is a problem of concentration.

0.8% w/w means that in 100 g of solution, we have 0.8 g of solute, in this case NaCl.

Let's determine the volume with the density.

Solution density = Solution mass / Solution volume

1.036 g/mL = 100 g / Solution volume

Solution volume = 100 g / 1.036 g/mL → 96.5 mL

Let's calculate molarity (mol/L)

We convert the mass to moles (mass / molar mass)

0.8 g / 58.45 g/mol = 0.0137 moles

We must convert the volume of solution to L.

Molarity is mol/L, moles of solute in L of solution.

96.5 mL . 1L/1000 mL = 0.0965 L

0.0137 mol / 0.0965 L = 0.14 M

Let's determine molality and mole fraction.

Molality are moles of solute in 1 kg of solvent (mol/kg)

Mass of solution = Mass of solute + Mass of solvent

100 g = 0.8 g + Mass of solvent

100 g - 0.8 g = Mass of solvent → 99.2 g

Then, we must convert the mass of solvent to kg

99.2 g . 1kg / 1000 g = 0.0992 kg

Molality: 0.0137 mol / 0.0992 kg  → 0.14 m

Mole fraction → moles of solute / moles of solute + moles of solvent

Let's find out the moles of solvent ( mass / molar mass)

99.2g / 18 g/mol = 5.511 mol

Total moles = 5.511 + 0.0137 → 5.5247 moles

Mole fraction = 0.0137 / 5.5247 → 2.48×10⁻³

8 0
3 years ago
g Glycolysis is the process by which energy is harvested from glucose by living things. Several of the reactions of glycolysis a
Alex787 [66]

Answer:

A and B are unfavorable reactions.

Explanation:

In chemical thermodynamics, an endergonic reaction  is also called a nonspontaneous reaction or an unfavorable reaction. it's a chemical reaction in which the change in free energy is positive, and energy is absorbed.

In chemical thermodynamics, an exergonic reaction  is also called a spontaneous reaction or a favorable reaction. it's a chemical reaction in which the change in free energy is negative.

ΔG>0

If the Gibbs  free energy of the reaction is positive than the reaction will be non spontaneous .

If the Gibbs  free energy of the reaction is negative than the reaction will be spontaneous

Gibbs free energy is an energy which that can be use to convert into useful work.

ΔG=ΔH-TΔS

with ΔG= Gibbs free energy

with ΔH =  enthalpy of reaction

with T = temperature of eh reaction

ΔS = Entropy change

The reaction A: Pi+glucose⟶glucose-6-phosphate+H2O

The ΔG is positive. This is an nonspontaneous reaction or an unfavorable reaction

The reaction B: Pi+fructose-6-phosphate⟶fructose-1,6-bisphosphate+H2O

The ΔG is positive. This is an nonspontaneous reaction or an unfavorable reaction.

The reaction C: ATP+H2O⟶ADP+Pi

The ΔG is negative. This is a spontaneous reaction or a favorable reaction.

A and B are unfavorable reactions.

6 0
3 years ago
Given the following data on a 6 foot tall, 210 pound male, perform the appropriate calculations and evaluate the values related
sladkih [1.3K]
A correct B incorrect C incorrect E correct
3 0
3 years ago
How many milliliters of sodium metal, with a density of 0.97 g/mL, would be needed to produce 43.6 grams of sodium hydroxide in
GaryK [48]

Answer is: 25.84  milliliters of sodium metal.

Balanced chemical reaction: 2Na + 2H₂O → 2NaOH + H₂.

d(Na) = 0.97 g/mL; density of sodim.

m(NaOH) = 43.6 g; mass of sodium hydroxide.

n(NaOH) = m(NaOH) ÷ M(NaOH).

n(NaOH) = 43.6 g ÷ 40 g/mol.

n(NaOH) =1.09 mol; amount of sodium hydroxide.

From chemical reaction: n(NaOH) : n(Na) = 2 : 2 (1: 1).

n(Na) = 1.09 mol.

m(Na) = 1.09 mol · 23 g/mol.

m(Na) = 25.07 g; mass of sodium.

V(Na) = m(Na) ÷ d(Na).

V(Na) = 25.07 g ÷ 0.97 g/mL.

V(Na) = 25.84 mL.

7 0
3 years ago
How many hours will it take for the concentration of methyl isonitrile to drop to 14.0 %% of its initial value?
tiny-mole [99]

This is an incomplete question, here is a complete question.

The rearrangement of methyl isonitrile (CH₃NC) to acetonitrile (CH₃NC) is a first-order reaction and has a rate constant of 5.11 × 10⁻⁵ s⁻¹ at 472 K. If the initial concentration of CH₃NC is 3.00 × 10⁻² M :

How many hours will it take for the concentration of methyl isonitrile to drop to 14.0 % of its initial value?

Answer : The time taken will be, 10.7 hours

Explanation :

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 5.11\times 10^{-5}s^{-1}

t = time passed by the sample  = ?

a = let initial amount of the reactant  = 100

a - x = amount left after decay process = 14 % of 100 = 14

Now put all the given values in above equation, we get

t=\frac{2.303}{5.11\times 10^{-5}}\log\frac{100}{14}

t=38482.72s=\frac{38482.72}{3600}=10.7hr

Therefore, the time taken will be, 10.7 hours

7 0
3 years ago
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