Question

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Answer 1

Answer:

Q1. 0.82 mol

Q2. 9.20 g

Explanation:

Question 1

Step 1: Given and required data

• Mass of NaHCO₃ (m): 68.88 g

• Molar mass of NaHCO₃ (M): 84.01 g/mol

Step 2: Calculate the moles (n) corresponding to 68.88 g of NaHCO₃

We will use the following expression.

n = m/M

n = 68.88 g/(84.01 g/mol) = 0.82 mol

Question 2

Step 1: Given data

• Moles of NaOH (n): 0.23 mol

• Molar mass of NaOH (M): 40.00 g/mol

Step 2: Calculate the mass (m) corresponding to 0.23 moles of NaOH

We will use the following expression.

m = n × M

m = 0.23 mol × 40.00 g/mol = 9.20 g