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Lelu [443]
3 years ago
6

Can someone help me with my stoichiometry homework, it is due tonight.

Chemistry
1 answer:
AleksandrR [38]3 years ago
6 0

Answer:

1. 1 mole of NaCl.

2. 1 mole of H₂O.

Explanation:

The balanced equation for the reaction is given below:

HCl + NaOH —> NaCl + H₂O

From the balanced equation above,

1 mole of HCl reacted with 1 mole of NaOH to produce 1 mole of NaCl and 1 mole of H₂O.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above, we can see that 1 mole of HCl reacted completely with 1 mole of NaOH. Therefore, HCl is the limiting reactant and NaOH is the excess reactant since we have 3.6 moles of NaOH.

1. Determination of the amount of NaCl produced from the reaction.

NOTE: The limiting reactant is used to determine the maximum amount produced since all of it is consumed in the reaction.

The limiting reactant is HCl and the amount of NaCl produced can be obtained as follow:

From the balanced equation above, we can see that 1 mole of HCl reacted to 1 mole of NaCl.

Thus, 1 mole of NaCl was produced.

2. Determination of the amount of H₂O produced from the reaction.

From the balanced equation above, it is evident that 1 mole of HCl reacted to produce 1 mole of H₂O.

Thus, 1 mole of H₂O was produced.

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As the ionic compound decreases in size, the melting point __
telo118 [61]

Answer:

A. increase

Explanation:

the smaller the size of the ionic compounds, the more closer they get packed together. This means electrostatic attraction also increases, which means the ionic bonds gets stronger...therefore increases the melting point

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What type of energy is produced by a geyser? A.Chemical energy B.Thermal energy C.Nuclear energy D.Radiant energy
Tatiana [17]
B. thermal energy is produced by a geyser
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Read 2 more answers
A 10.0 mL sample of 1.18 M AgNO3 is diluted to a final volume of 250.00 mL. Whats the final concentration?
Daniel [21]

Answer:

Final concentration M2 = 0.0472 M

Explanation:

Given:

Initial volume V1 = 10 ml

Initial concentration M1 = 1.18 M

Final volume V2 = 250 ml

Find:

Final concentration M2

Computation:

Using conservation of volume;

(Initial volume)(Initial concentration) = (Final volume)(Final concentration)

M1V1 = M2V2

(1.18)(10) = (Final concentration M2)(250)

(1.18)(10) / 250 = (Final concentration M2)

Final concentration M2 = 11.8 / 250

Final concentration M2 = 0.0472 M

4 0
3 years ago
2C2H2(g) 5O2(g) → 4CO2(g) 2H2O(g) This is a balanced equation for the combustion of acetylene (C2H2). How many moles of oxygen(O
Fudgin [204]

The moles of oxygen required to completely react with 1 moles of acetylene is 2.5 mol.

The balanced chemical equation for the reaction is given as:

\rm 2\;C_2H_2\;+\;5\;O_2\;\rightarrow\;4\;CO_2\;+\;2\;H_2O

<h3>Computation for moles of Oxygen required</h3>

The stoichiometric coefficient in the balanced chemical equation gives the information for the moles of products and reactants in the reaction.

From the given balanced chemical equation, for reacting with 1 mole of acetylene, 5 moles of oxygen is required.

The moles of oxygen required to react with 1 mole of acetylene are:

\rm 2\;mol\;C_2H_2=5\;mol\;O_2\\\\1\;mol\;C_2H_2=\dfrac{5}{2}\;\times\;1\;mol\;O_2\\\\ 1\;mol\;C_2H_2=2.5\;mol\;O_2

The moles of oxygen required to completely react with 1 moles of acetylene is 2.5 mol.

Learn more about moles produced, here:

brainly.com/question/10606802

8 0
2 years ago
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