Please answer this question

Chemistry

2 answers:

Svetradugi [14.3K]3 years ago

7 0

Answer:

............................................

Explanation:

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Flura [38]3 years ago

3 0

A

this is because 30 degrees celsius is 86 degrees Fahrenheit

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The R group or side chain of the amino acid leucine is non-polar. The R group of serine is polar. Where would you expect to find

Pani-rosa [81]

Answer:

Serine will be on the exterior of the globular protein while leucine on the interior of the globular proteins

Explanation:

The nature or solubility of the side cham determines the poition of amino acid on the globular protein and it is either hydrophilic or hydrophobic.

Serine is an hydrophilic amino acid and so it is position on the surface of the globular protein (Exterior)

While Leucine side chain is hydrophobic in nature is positioned on the interior of the globular protein.

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3 years ago

Explains how commercial land use negatively impacts watersheds?

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Polluted water. The growing crops and climate variability change. Basically the farming

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The liquid-phase reaction follows an elementary rate law and is carried out isothermally in a flow system. The concentrations of

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4 years ago

2. Balance the equation below, and answer the following question: What volume of chlorine gas, measured at STP, is needed to com

Juliette [100K]

Balanced equation: 2Na(s) + Cl₂(g) ---> 2NaCl(s)

when we have STP conditions, we can use this conversion: 1 mol = 22.4 L

first, we have to convert grams to molecules using the molar mass, and then use mole to mole ratio from the balanced equation.

molar mass of Na= 23.0 g/mol
ratio: 2 mol Na= 1 mol Cl₂ (based on coefficients of balanced equation)

calculations:

$6.25 g Na ( \frac{1 mol Na}{23.0 g} ) ( \frac{1 mol Cl_2}{2 mol Na} ) ( \frac{22.4 L}{1 mol} )= 3.04 L$

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3 years ago

Using the equations 2 Sr(s) + O₂ (g) → 2 SrO (s) ∆H° = -1184 kJ/mol SrO (s) + CO₂ (g) → SrCO₃ (s) ∆H° = -234 kJ/mol CO₂ (g) → C(

kkurt [141]

<u>Answer:</u> The $\Delta H^o_{rxn}$ for the reaction is 72 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

$2SrCO_3(s)\rightarrow 2Sr(s)+2C(s)+3O_2(g)$ $\Delta H^o_{rxn}=?$