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Lera25 [3.4K]
3 years ago
6

Please answer this question

Chemistry
2 answers:
Svetradugi [14.3K]3 years ago
7 0

Answer:

............................................

Explanation:

............................................

Flura [38]3 years ago
3 0
A

this is because 30 degrees celsius is 86 degrees Fahrenheit
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Please help don’t understand this I attached the question
Rasek [7]

Answer:

58.32

Explanation:

The mass number is one mole and for Mg it is 24.306 for O it is 15.999 and for H it is 1.008. because O and H have 2, you multiply them by 2 and add all the numbers and it equals 58.32

8 0
1 year ago
Read 2 more answers
Phase or state of matter​
klio [65]

Answer:

state of mater

Explanation:

6 0
3 years ago
Find the value of x in the triangle
myrzilka [38]

Answer:

55.52°

Explanation:

Concept tested: Sine rule of triangles

We need to know the sine rule

  • According to sine rule, if the three sides of a triangle are a, b and c and the corresponding angles, A, B and C
  • Then, \frac{a}{SinA}=\frac{b}{SinB}=\frac{c}{SinC}

In this case;

  • If we take, a = 5.7 units and A = 70°, and

         b= 5 units, B = x°

  • Using the sine rule we can find the value of x

Therefore;

\frac{a}{SinA}=\frac{b}{SinB}

Then;

\frac{5.7}{Sin70}=\frac{5}{Sinx}

6.0658=\frac{5}{sinx}

Sinx=0.8243

Therefore, X = 55.52°

Therefore, the value of x in the triangle is 55.52°

6 0
3 years ago
a sample of unknown material weighs 500 n in air and 200 n when immesersed in alcholol with a specfic gravity of 0.7 what is the
svet-max [94.6K]

Answer: The mass density is 1166.36 kg/m^{3}.

Explanation:

Given: Weight of sample in air (F_{air}) = 500 N

Weight of sample in alcohol (F_{alc}) = 200 N

Specific gravity = 0.7 = 0.7 \times 1000 = 700 kg/m^{3}

Formula used to calculate Buoyant force is as follows.

F_{B} = F_{air} - F_{alc}\\= 500 - 200 \\= 300 N

Hence, volume of the material is calculated as follows.

V = \frac{F_{B}}{\rho \times g}

where,

F_{B} = Buoyant force

\rho = specific gravity

g = acceleration due to gravity = 9.81

Substitute the values into above formula.

V = \frac{F_{B}}{\rho \times g}\\= \frac{300}{700 \times 9.81}\\= \frac{300}{6867}\\= 0.0437 m^{3}

Now, mass of the material is calculated as follows.

mass = \frac{F_{air}}{g}\\= \frac{500 N}{9.81}\\= 50.97 kg

Therefore, density of the material or mass density is as follows.

Density = \frac{mass}{volume}\\= \frac{50.97 kg}{0.0437 m^{3}}\\= 1166.36 kg/m^{3}

Thus, we can conclude that the mass density is 1166.36 kg/m^{3}.

7 0
2 years ago
The molar mass of HgO is 216.59 g/mol. The molar mass of O2 is 32.00 g/mol. How many moles of HgO are needed to produce 250.0 g
Irina-Kira [14]
A reaction in which Oxygen (O₂) is produced from Mercury Oxide (HgO) would be a decomposition reaction.
           2HgO    →    2Hg    +    O₂

If 250g of O₂ is needed to be produced,
then the moles of oxygen needed to be produced = 250g  ÷  32 g/mol
                                                                                     = 7.8125 mol

Now, the mole ratio of Oxygen to Mercury Oxide is  1  :  2
∴ if the moles of oxygen =  7.8125 mol
then the moles of mercury oxide = 7.8125 mol × 2
                                                        = 15.625 mol


Thus the number moles of HgO needed to produce 250.0 g of O₂ is 15.625 mol
 
6 0
3 years ago
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