All categories

3 years ago

What part of an original isotope’s number of atoms remains have two half-lives?

Chemistry

1 answer:

KIM [24]3 years ago

3 0

After two half-lives, one fourth of the original isotope’s atom remain.

You might be interested in

Why chlorine is more reactive than hydrogen

Lynna [10]

Answer:

<em>Hi Todoroki here!!! </em>

Explanation:

Chlorine has the electron configuration [Ne]3s 2 3p 5, with the seven electrons in the third and outermost shell acting as its valence electrons. Like all halogens, it is thus one electron short of a full octet, and is hence a strong oxidising agent, reacting with many elements in order to complete its outer shell.

<em>Your welcome!!</em>

7 0

3 years ago

What is the magnetic quantum number value for an element with n = 1?

Citrus2011 [14]

Answer:

0, l is n-1 always, ml is l to -l

6 0

3 years ago

What electrically neutral atom will have an electron configuration of 1s2 2s2 2p4?

abruzzese [7]

Answer:- oxygen.

Explanations:- The electronic configuration is given and we are asked to figure out the electrically neutral atom that will have the electron configuration, $1s^22s^22p^4$ .

The sum of electrons for this electron configuration is 8. If we look at the periodic table then 8 is the atomic number of oxygen.

So, the electrically neutral atom for the given electron configuration is oxygen.

6 0

2 years ago

A balloon is filled to a volume of 1.6 L at 278 K. The balloon is left outside overnight and the temperature has dropped to 253

german

Explanation:

Charles' law gives the relationship between the volume and the temperature of the gas. Mathematically,

Volume ∝ Temperature

i.e. $\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}$

We have, V₁ = 1.6 L, T₁ = 278 K, T₂ = 253, V₂=?

$V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{1.6\times 253}{278}\\\\V_2=1.45\ L$

So, the new volume is 1.45 L.

6 0

2 years ago

For lunch, a patient consumed 3 oz of skinless chicken, 3 oz of broccoli, 1 medium apple, and 1 cup of nonfat milk (see Table 3.

Volgvan

Lunch of a patient has 3 oz skinless chicken, 3 oz of broccoli, 1 medium apple, and 1 cup of nonfat milk

Energy content of 3 oz skinless chicken is = 110 kcal

Energy content of 3 oz broccoli = 30 kcal

Energy content of 1 medium apple = 60 kcal

Energy content of 1 cup non-fat milk = 90 kcal

So the kilocalories of energy patient obtained from lunch

= 110 kcal+ 30 kcal + 60 kcal + 90 kcal = 290 kcal

3 0

2 years ago