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mojhsa [17]
3 years ago
13

What part of an original isotope’s number of atoms remains have two half-lives?

Chemistry
1 answer:
KIM [24]3 years ago
3 0
After two half-lives, one fourth of the original isotope’s atom remain.
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Most of the dissolved substance in sea water is: hydrogen chloride nitrogen sodium ANSWER NOW! I NEED HELP ASAP! WILL GIVE BRAIN
VMariaS [17]

Answer: Sodium chloride

Explanation:

Ocean water contains a number of substances. When a substance which has ionic bonds is dissolved in water it takes the form of ions.

The most common ions in ocean water are sodium and chloride. These are the ions formed when common salt, sodium chloride (NaCl) is dissolved in water.

Sodium chloride accounts for about 3% of ocean water by mass.

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Which type of molecule forms structures in cells and stores energy? I NEED HELP
olga2289 [7]

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Lipid forms structures in cells and stores energy

Explanation:

7 0
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Nitrogen and hydrogen combine at a high temperature, in the presence of a catalyst, to produce ammonia. N2(g)+3H2(g)⟶2NH3(g) Ass
yaroslaw [1]

Answer:

moles of ammonia produced = 0.28 moles

Explanation:

The reaction is

N_{2}(g)+3H_{2}(g) --> 2NH_{3}(g)

As per equation, one mole of nitrogen will react with three moles of hydrogen to give two moles of ammonia

So 0.140 moles of nitrogen will react with = 3 X 0.140 moles of Hydrogen

             = 0.42 moles of hydrogen molecule.

this will give 2 X 0.140 moles of ammonia = 0.28 moles of ammonia

the moles of ammonia produced = 0.28 moles

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4 0
3 years ago
Each isotope has a unique half-life. The half-life of an isotope is the time taken for half of the starting quantity to decay (w
Tems11 [23]

Answer:

b. 17,190

Explanation:

Using the formula for C-14 dating,

t=\dfrac{ln(\dfrac{N}{N_0})t_\frac{1}{2}  }{-0.693}

where Present Value N =1/8 of Parent Sample

Initial Value, N_0=1

Half Life, t_\frac{1}{2}=5730 years

t=\dfrac{ln(\dfrac{1/8}{1})5730}{-0.693}

=17,190

Therefore the fossil is about 17190 years old.

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Element R and Element Q have the same number of valence electrons. These elements have similar chemical behavior, but element R
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Answer:

I dont now because I am in 6 class

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