To find the amount of atoms in a mole you will use Avragadro's constant. So 2.8 x 6.02 x 10^23 (2.8x 6.02 ten to the power of 23)
2.8x 6.02 10^23
Answer:
The answer is 916.67 g
Explanation:
48.0 wt% NaOH means that there are 48 g of NaOH in 100 g of solution. With this information and the molecular weight of NaOH (40 g/mol), we can calculate the number of mol there are in 100 g of this solution:
x 
= 0.012 mol NaOH/100 g solution
Finally, we need 0.11 mol in 1 liter of solution to obtain a 0.11 M NaOH solution.
0.012 mol NaOH ------------ 100 g solution
0.11 mol NaOH------------------------- X
X= 0.11 mol NaOH x 100 g/ 0.012 mol NaOH= 916.67 g
We have to weigh 916.67 g of 48.0%wt NaOH and dilute it in a final volume of 1 L of water to obtain a 0.11 M NaOH solution.
0.125 g=(0.125 g)(1000 mg/1g)=125 mg.
Then, we need 125 mg of ampicillin.
5 ml of liquid suspension contains 250 mg of ampicilling , therefore:
5 ml----------------250 mg of ampicilling
x--------------------125 mg of ampicilling
x=(5 ml * 125 mg of ampicilling) / 250 mg of ampicilling=2.5 ml
Answer: we require 2.5 ml
Answer:
Concentration, because the amounts of reactants and products remain constant after equilibrium is reached.
Explanation:
The rate of reaction refers to the amount of reactants converted or products formed per unit time.
As the reaction progresses, reactions are converted into products. This continues until equilibrium is attained in a closed system.
When equilibrium is attained, the rate of forward reaction is equal to the rate of reverse reaction, hence the concentration of reactants and products in the system remain fairly constant over time.
When deducing the rate of reaction, concentration of the specie of interest is plotted on the y-axis against time on the x-axis.
