Answer:
In the wild, boa constrictors typically eat wild pigs, monkeys, bats, birds, lizards, squirrels, and rats. Basically, they'll eat anything they can possibly catch.
<em>hope this helps!</em>
Answer:
Option B, not phosphorylated; inhibited
Explanation:
Glucose 6 acts as a catobolite repressant . A catobolite repressant which is usually a carbon compound inhibits the operon transcription. In the presence of glucose -6, unphosphorylated enzyme IIAGlc inhibits the transportation system and hence prevents the utilization of lactose. Glucose‐6‐phosphate and other non‐PTS carbon causes inducer exclusion thereby leading to dephosphorylation of enzyme IIAGl without getting transported.
Hence, option B is correct
The answer would be A. Because hemophilia is recessive and the Leopold carries the recessive trait
Answer:
The third one
C6H12O6 + 6O2 → 6CO2 + 6H2O.
Explanation:
The correct option is that the higher the temperature of Y the more colorless cells it contains and is denoted as option B.
<h3>What is Temperature?</h3>
This us defined as the degree of hotness or coldness of a body and is dependent on thermal energy.
High temperature will denature yeast as a result of its rich protein content and increasing the temperature will therefore leads to the presence of more colorless cells in Y which are able to act on it.
Read more about Temperature here brainly.com/question/2331658
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