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Natali [406]
3 years ago
8

5. a. Answer the following questions. What is density? Write a formula by showing the relation among density mass and volume.​

Physics
2 answers:
gtnhenbr [62]3 years ago
5 0

Answer:

Density is how compact something is. The relationship is M/V=D (Mass divided by Volume equals Density).

Explanation:

Ivenika [448]3 years ago
4 0

WHAT IS DENSITY:

Density is the degree of compactness of a substance.

EXAMPLE:

"a reduction in bone density"

FORMULA OF DENSITY:

The formula for density is d = M/V, where d is density, M is mass, and V is volume.

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What is magnetic declination?
sdas [7]
I believe its B ,<span> (the direction the north end of a </span>compass<span> needle points, corresponding to the direction of the Earth's </span>magnetic<span> field lines)</span>
5 0
3 years ago
Read 2 more answers
A ball is thrown horizontally from a 20-m-high building with a speed of 5.0m/s
KATRIN_1 [288]
1) Horizontal velocity, Vx

Vx is constant and equal to 5.0 m/s

The graph Vx(t) = 5.0 m/s is a horizontal line (parallel to the horizontal t-axis). that intercepts the vertical-axis at 5.0 and runs from t = 0 to t = 2.

2) Vertical velocity, Vy

Vy = gt = 10t

d = at^2 / 2 => tmax = √(2d / a) = √(2*20m/10m/s^2) = 2 s

Graph Vy is an inclined line with slope 10 m/s^2, that runs from t =0 to t = 2 s, and passes through the points (0,0), (1,10), and (2,20).










3 0
3 years ago
A motorcycle accelerated from 10 metre per second to 30 metre per second in 6 seconds. How far did it travel in this time ?
Ber [7]
U=10 m/s
v=30 m/s
t=6 sec

therefore, a=(v-u)/t
                   =(30-10)/6
                   =(10/3) ms^-2

now, displacement=ut+0.5*a*t^2
                              =60+ 0.5*(10/3)*36
                              =120 m
And you can solve it in another way:

v^2=u^2+2as
or, s=(v^2-u^2)/2a
       =(900-100)/6.6666666.......
       =120 m

7 0
4 years ago
Narysuj wykres zależności v(t) jeśli w chwili początkowej t=0 V=10m/s w każdej sekundzie szybkość zmniejsza się o 1m/s . Po jaki
irina1246 [14]

1) See graph in attachment

2) 10 s

3) 50 m

Explanation:

1)

In this problem, we have an object initially moving with a velocity of

v = 10 m/s

when the time is

t = 0 s

Then, we are told that the speed of the object is decreasing by 1 m/s every  second. This means that on a velocity-time graph, the motion will be represented by a straight line, starting from v = 10 when t = 0, and decreasing by 1 m/s every second.

The result can be found in the graph in attachment.

Moreover, we can also infer that the motion of the object is accelerated (because velocity is changing), and that the acceleration is constant and it is equal to

a=1 m/s^2

which is equivalent to the gradient of the line in the velocity-time graph.

2)

In this part, we want to find after what time the body will stop its motion.

To do that, we can use the following suvat equation:

v=u+at

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time

In this problem:

u = 10 m/s is the initial velocity of the body

a=-1 m/s^2 is the acceleration

v = 0 m/s, because we want to find the time T at which the body will stop

Re-arranging the equation, we find:

T=-\frac{u}{a}=-\frac{10}{-1}=10 s

3)

In order to find the total distance covered by the body during its accelerated motion, we have to use another suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the distance covered

u is the initial velocity

t is the time

a is the acceleration

In this problem:

u = 10 m/s is the initial velocity

a=-1 m/s^2 is the acceleration

t = 10 s is the time it takes for the body to stop (found in part 2)

Solving for s, we find the distance covered:

s=(10)(10)+\frac{1}{2}(-1)(10)^2=50 m

7 0
4 years ago
Which best describes what occurs when an object takes in a wave as the wave hits it?.
statuscvo [17]

Answer:

Absorption

Explanation:

7 0
2 years ago
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