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trasher [3.6K]
3 years ago
13

Where do we use friction in day to day life​

Physics
1 answer:
laila [671]3 years ago
7 0

Answer:

walking in ground

while playing carrom

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How can a large force result in a relatively small power?
Sav [38]

Answer:

hey mate here is your answer

So if an object has a very small velocity (not moving very far over time, even though a large force may be applied to it, the Power will remain small. ... Stepping on the gas, or "speeding up" the car, is applying a force which will increase velocity and increase power.

please mark me as a brainliest

8 0
2 years ago
A car speeds up from 13 m/s to 23 m/s in 30 seconds. What is the
Lapatulllka [165]

acceleration of the car = 0.33 m/s²

Explanation:

To calculate the acceleration of the car we use the following formula:

acceleration = change in velocity / time

change in velocity = final velocity - initial velocity

change in velocity = 23 m/s - 13 m/s = 10 m/s

change in velocity = 10 m/s

acceleration = 10 m/s / 30 s

acceleration = 0.33 m/s²

Learn more about:

acceleration

brainly.com/question/4134594

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#learnwithBrainly

8 0
3 years ago
3. Do you have an issue with the NSA monitoring citizens’ phone calls, text messages, emails, etc.?
goblinko [34]
<span> If You Have Nothing to Hide, You Have Nothing to Fear</span>
8 0
3 years ago
A spring of spring constant 30.0 N/m is attached to a 2.3 kg mass and set in motion. What is the period and frequency of vibrati
coldgirl [10]

Answer:

1. The period is 1.74 s.

2. The frequency is 0.57 Hz

Explanation:

1. Determination of the the period.

Spring constant (K) = 30 N/m

Mass (m) = 2.3 Kg

Pi (π) = 3.14

Period (T) =?

The period of the vibration can be obtained as follow:

T = 2π√(m/K)

T = 2 × 3.14 × √(2.3 / 30)

T = 6.28 × √(2.3 / 30)

T = 1.74 s

Thus, the period of the vibration is 1.74 s.

2. Determination of the frequency.

Period (T) = 1.74 s

Frequency (f) =?

The frequency of the vibration can be obtained as follow:

f = 1/T

f = 1/1.74

f = 0.57 Hz

Thus, the frequency of the vibration is 0.57 Hz

4 0
3 years ago
An Airbus A380 airliner can takeoff when its speed reaches 80 m/s. Suppose its engines together can produce an acceleration of 3
Tomtit [17]

Answer:

(a). The time is 26.67 sec.

(b). The distance traveled during this period is 1066.9 m.

Explanation:

Given that,

Speed = 80 m/s

Acceleration = 3 m/s

Initial velocity = 0

(a). We need to calculate the time

Using equation of motion

v = u+at

t = \dfrac{v-u}{a}

Put the value into the formula

t = \dfrac{80-0}{3}

t =26.67\ sec

The time is 26.67 sec.

(b). We need to calculate the distance traveled during this period

Using equation of motion

s = ut+\dfrac{1}{2}at^2

s = 0+\dfrac{1}{2}\times3\times(26.67)^2

s =1066.9\ m

The distance traveled during this period is 1066.9 m.

Hence, This is the required solution.

7 0
3 years ago
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