Answer:
hey mate here is your answer
So if an object has a very small velocity (not moving very far over time, even though a large force may be applied to it, the Power will remain small. ... Stepping on the gas, or "speeding up" the car, is applying a force which will increase velocity and increase power.
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acceleration of the car = 0.33 m/s²
Explanation:
To calculate the acceleration of the car we use the following formula:
acceleration = change in velocity / time
change in velocity = final velocity - initial velocity
change in velocity = 23 m/s - 13 m/s = 10 m/s
change in velocity = 10 m/s
acceleration = 10 m/s / 30 s
acceleration = 0.33 m/s²
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acceleration
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Answer:
1. The period is 1.74 s.
2. The frequency is 0.57 Hz
Explanation:
1. Determination of the the period.
Spring constant (K) = 30 N/m
Mass (m) = 2.3 Kg
Pi (π) = 3.14
Period (T) =?
The period of the vibration can be obtained as follow:
T = 2π√(m/K)
T = 2 × 3.14 × √(2.3 / 30)
T = 6.28 × √(2.3 / 30)
T = 1.74 s
Thus, the period of the vibration is 1.74 s.
2. Determination of the frequency.
Period (T) = 1.74 s
Frequency (f) =?
The frequency of the vibration can be obtained as follow:
f = 1/T
f = 1/1.74
f = 0.57 Hz
Thus, the frequency of the vibration is 0.57 Hz
Answer:
(a). The time is 26.67 sec.
(b). The distance traveled during this period is 1066.9 m.
Explanation:
Given that,
Speed = 80 m/s
Acceleration = 3 m/s
Initial velocity = 0
(a). We need to calculate the time
Using equation of motion
Put the value into the formula
The time is 26.67 sec.
(b). We need to calculate the distance traveled during this period
Using equation of motion
The distance traveled during this period is 1066.9 m.
Hence, This is the required solution.
