The work and heat transfer isothermal internally reversible process.
An isothermal procedure is a thermodynamic procedure in which the temperature of a gadget stays consistent. The transfer of heat into or out of the gadget occurs so slowly that thermal equilibrium is maintained. The melting of ice at 0 diploma is an example of isothermal technique. The reaction in a warmth pump is an example of isothermal manner. In Isothermal manner temperature is constant for the duration of the procedure and follows Boyles regulation.
Given,
Gas at initially P1= 2.8 bar
P2 = 14 bar
isothermal reversible process,
Compressed pressure at 60°C
(a) R = 134a
For Refrigerant 134a R134a
At P1 = 14 bar T1 = 600C
S1 = 0.9389 KJ/Kg K
V1 = 264.64 KJ/kg
At
P2 = 2.8 bar T2 = 600C
S2 = 1.1142 KJ/Kg K
V2 = 278.56 KJ/kg
T = 60 + 273 = 333K
Q= 2 Tds
2 Q=T ſ ds
= T(S2-S1)
= 333 ( 1.1142 - 0.9389 )
= 58.3749 KJ/Kg
Heat transfer Q = 58.3749 KJ/Kg
(b) air as an ideal gas.
Q= 2 Tds
2 Q=T ſ ds
= T(S2-S1)
=T-R In P2 P1
= 333 * -0.287 In 2.8 14
= 153.81 KJ/Kg
Heat transfer Q = 153.81 KJ/Kg
W = Q - ΔV
= 28.3749 - (278.56-264.64)
= 14.4549 KJ/Kg
Work W = 14.4549 KJ/Kg
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Answer:
<h2>Magnetic field strength in that region is 1.2 T</h2>
Explanation:
As we know by the formula of radius of charge moving in external field is given as

so we will have




now we have

now we have

Answer:
It will take 2.68 minutes for them to reach each other.
Explanation:
We use the two following kinematic equations, making the final position the same (for the moment they meet each other):
locomotive 1 --> 
locomotive 2 --> 
we make the two xf equal, and solve for the time (t) using v = 95 km/h:

converting the hours into minutes by multiplying this value times 60;
t = 2.68 minutes
Answer:
0.125 A
Explanation:
From the question given above, the following data were obtained:
Power (P) = 30 W
rms voltage (Vrms) = 240 V
rms Current (Irms) =?
The power in an electric circuit is given by the following equation:
Power (P) = current (I) × voltage (V)
With the above formula, we can obtain the rms current flowing through the bulb as shown below:
Power (P) = 30 W
rms voltage (Vrms) = 240 V
rms Current (Irms) =?
P = Irms × Vrms
30 = Irms × 240
Divide both side by 240
Irms = 30 / 240
Irms = 0.125 A
Thus, the rms current flowing through the light bulb is 0.125 A
Answer:
the results will be the same.it may be